If two distinct lines intersect, which is NOT necessarily true?

Mathematics

1 answer:

Inessa05 [86]3 years ago

8 0

The lines are perpendicular.

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The crew of apollo 17 consisted of 2 pilots and a geologist. Suppose that nasa had actually trained 9 pilots and 4 geologists as

Troyanec [42]

They could have assembled total 336 different possible crews.

Explanation

Total number of trained pilots is 9 and geologists is 4.

The crew should be consisted of 2 pilots and 1 geologist. That means, 2 pilots are chosen from total 9 and 1 geologist is chosen from total 4.

Number of ways for choosing 2 pilots from 9 $= ^9C_{3} =84$ and

Number of ways for choosing 1 geologist from 4 $=^4C_{1}= 4$

So, the total possible number of different crews they could have assembled $=84*4= 336$

8 0

3 years ago

Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²

IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

$a^2-b^2=(a-b)(a+b)$

Let us examine each of the given equation

$\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}$ $\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}$ $\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}$ $\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}$

From the above,