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2 years ago

What is the slope of a line that is perpendicular to the line y = -1/2 x + 5?

1 answer:

8 0

The answer is D. 2

The slope of this line is -1/2
Two lines are perpendicular when multiplying their slopes = -1

The only answer that gives this is D:
(-1/2) * 2 = -1

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Juan divided 1/2 jar of fish food into 7 equal parts. He feeds his fish one part each day.

amid [387]

1/14 is the correct answer

5 0

2 years ago

Read 2 more answers

Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Tems11 [23]

Answer and explanation:

To find : Calculate to the nearest 1/10th meter the length of the side of a 7th, 12th, and 30th hectare square plot.

Solution :

The area of the square is given by,

$A=s^2$ where s is the side length.

We know, $1 \text{ hectare}=10,000\ m^2$

1) The area of square plot is 7 hectare.

Area in meter square is $A=7\times 10000=70000\ m^2$

Substitute the value in the formula,

$70000=s^2$

$\sqrt{70000}=s$

$264.57=s$

Side nearest to 1/10th meter is 264.8 meter.

2) The area of square plot is 12 hectare.

Area in meter square is $A=12\times 10000=120000\ m^2$

Substitute the value in the formula,

$120000=s^2$

$\sqrt{120000}=s$

$346.41=s$

Side nearest to 1/10th meter is 346.4 meter.

3) The area of square plot is 30 hectare.

Area in meter square is $A=30\times 10000=300000\ m^2$

Substitute the value in the formula,

$300000=s^2$

$\sqrt{300000}=s$

$547.72=s$

Side nearest to 1/10th meter is 547.7 meter.

5 0

2 years ago

7 2,451 people came to watch the Easter parade. 745 of those people were adults. How many children came to the parade?

lukranit [14]

Take to total number of people attending and subtract the number of adults. The remainder are the children

2,451 - 745 = 1,706

7 0

2 years ago

Find the magnitude and direction (in degrees) of the vector. (Assume 0° ≤ < 360°.)

ddd [48]

$6i~~ + ~~2\sqrt{3}j\implies < \stackrel{a}{6}~~,~~\stackrel{b}{2\sqrt{3}} > \\\\[-0.35em] ~\dotfill\\\\ \stackrel{magnitude}{\sqrt{a^2+b^2}}\implies \sqrt{6^2+(2\sqrt{3})^2}\implies \sqrt{36+(2^2\cdot 3)}\implies \sqrt{36+12}\implies \sqrt{48} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{direction}{tan^{-1}\left( \cfrac{b}{a}\right)}\implies tan^{-1}\left( \cfrac{2\sqrt{3}}{6} \right)\implies tan^{-1}\left( \cfrac{\sqrt{3}}{3} \right) \\\\\\ tan^{-1}\left( \cfrac{1}{\sqrt{3}} \right)\implies 30^o$

3 0

1 year ago

Fatima is shading this model to show 0.08x3 . shade the correct amount of boxes that will show the product

Karo-lina-s [1.5K]

Shade 0.08 3 times

In total that's 24 hundreths to shade

For more help, please upload a picture

Hope this helps!!

7 0

2 years ago