<u>Answer:</u>
The probability of selecting such number =
<u>Explanation:</u>
4-digit numbers start from 1000 and ends at 9999
So, there are 9000 4-digit numbers present
There are 90 palindrome numbers (which reads the same forward and backward) present between 1000-9999. They are 1001; 1111; 1221; 1331; ... 1001; 1111; 1221; 1331; ... to 9669; 9779; 9889; 9999; 9669; 9779; 9889; 9999
Therefore, the probability of selecting such number =
Divide negative 16 by both sides
v=2
Answer:
1+1= 11
1Step-by-step explanation:
I might be wrong so if i am right pls give me a thanks
If two triangles are similar then the
corresponding sides are in proportion. Thus,
AB / AU = BC / UV = AC / AV
AB / (20x+108) = 703 / 444
Where AB is equivalent to:
AB = AU + UB
AB = 20x + 108 + 273
AB = 20x + 381
Therefore going back to the first equation:
(20x + 381) / (20x + 108)
= 703/444
444 (20x + 381) = 703 (20x + 108)
8880x + 169164 = 14060x + 75924
14060x - 8880x = 169164 – 75924
5180 x = 93240
x = 93240 / 5180
<span>x = 18</span>
