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Karolina [17]
3 years ago
15

The price of a commodity has fell down by 15% so that priya can buy 3 more commodities for Rs 1700. What was the original price

of the commodity.
​
Mathematics
1 answer:
erastova [34]3 years ago
7 0

Answer:

2,000

Step-by-step explanation:

write out an equation that represents the problem. the original price X fell by 15% to a new price of 1700:

X - (X*15%) = 1700

X(1-0.15) =1700

X=1700/(1-0.15)

X=2,000

convert 15% to decimal form:

15%=0.15

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Answer the following questions using what you've learned from this unit. Write your answers in the
sesenic [268]

Answer:

x=-3

Step-by-step explanation:

5(x - 4) + 3x - 9x = 6 - (2x + 5) + 8x

(remove parentheses)

5x-20+3x-9x=6-2x-5+8x

(collect like terms and calculate)

-x-20=1+6x

(move the terms)

-x-6x=1+20

(collect like terms and calculate)

-7x=21

(divide both sides)

x=-3

(your answer :))

8 0
3 years ago
Ask Your Teacher The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particula
Georgia [21]

Answer:

The level is L = 0.084

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.08, \sigma = 0.01, n = 36, s = \frac{0.01}{\sqrt{36}} = 0.0017

What is the level L such that the probability that the average NOX level x for the fleet is greater than L is only 0.01?

This is X when Z has a pvalue of 1-0.01 = 0.99. So it is X when Z = 2.325.

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

2.325 = \frac{X - 0.08}{0.0017}

X - 0.08 = 2.325*0.0017

X = 0.084

The level is L = 0.084

4 0
4 years ago
Jessica, Chau, and Kareem sent a total of 84 text messages during the weekend. Kareem sent 4 times as many messages as Chau. Jes
swat32

Answer:

Number of messages sent by Chau = 15

Number of messages sent by Kareem = 4 * 15 = 60

Number of messages sent by Jessica = 15 - 6 = 9

Step-by-step explanation:

Let number of messages sent by Chau = c

Number of messages sent by Kareem = 4 times as Chau

                                                                = 4 * c = 4c

Number of messages sent by Jessica = 6 fewer messages than Chau

                                                               = c - 6

Total messages = 84

<u>c + 4c + c</u> - 6 = 84                {Combine like terms}

<u>6c</u> - 6 = 84         {Add 6 to both sides}

6c  = 84 + 6

6c = 90   {Divide both sides by 6}

c = 90/6

c = 15

Number of messages sent by Chau = 15

Number of messages sent by Kareem = 4 * 15 = 60

Number of messages sent by Jessica = 15 - 6 = 9

3 0
3 years ago
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Oliga [24]

Answer:

304.8

Step-by-step explanation:

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3 years ago
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Please help me please please please
AURORKA [14]

Answer:

y= -9

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Step-by-step explanation:

6 0
3 years ago
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