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3 years ago

Write an equation for the graph below.

Mathematics

2 answers:

topjm [15]3 years ago

8 0

Answer:

y= 25x

Step-by-step explanation:

jolli1 [7]3 years ago

4 0

Answer:

The line can be defined as y = 25x.

Step-by-step explanation:

First we find two points that this falls on. (0, 0) and (200, 8) clearly visible points that it falls on. If we take common factors out of that, we get (1, 25).

With those points, we have the slope of the function. Slope is equal to Δy/Δx, so in this case its 25/1 or just 25

Normally, to define a line, we would take a point on it and use it as reference, defining the line as (y - y1) = s(x - x1). In this case though, because the line intersects point (0, 0), we don't even need to translate it. We can simply say:

y = sx

We already have our slope of 25, so the our line function is:

y = 25x

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arsen [322]

Answer:

what

Step-by-step explanation:

3 0

3 years ago

For what values of c does the binomial 5-3c take on a value which is greater than 80?

Ganezh [65]

Answer: c > -25

From the question you can get the equation:
5 - 3c > 80; subtract 5 from both side
-3c > 75; divide -3 from both side
c > -25
So numbers including: -24, -23, -22, -21…
are all numbers that could work

7 0

3 years ago

What is another way to write 56

SashulF [63]

Answer:

$\frac{112}{2}$

Step-by-step explanation:

Another way to express 56 is $\frac{112}{2}$ because they are equal values.

3 0

3 years ago

Read 2 more answers

The distribution of lifetimes of a particular brand of car tires has a mean of 51,200 miles and a standard deviation of 8,200 mi

Orlov [11]

Answer:

a) 0.277 = 27.7% probability that a randomly selected tyre lasts between 55,000 and 65,000 miles.

b) 0.348 = 34.8% probability that a randomly selected tyre lasts less than 48,000 miles.

c) 0.892 = 89.2% probability that a randomly selected tyre lasts at least 41,000 miles.

d) 0.778 = 77.8% probability that a randomly selected tyre has a lifetime that is within 10,000 miles of the mean

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 51200, \sigma = 8200$