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Usimov [2.4K]
3 years ago
15

Help on questions 11 and 15 Add and simplify if possible

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}
nika2105 [10]3 years ago
4 0
\frac{16+x}{x^{3} } +  \frac{7-4x}{ x^{3} } 
 \\ 16+x+7-4x = 23-3x
 \\  \frac{23 -3x}{ x^{3} }
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\frac{5}{t-1}  +\frac{3}{t} 
  \\ \\  \frac{5t+(t-1)(3)}{(t-1)(t)} 
 \\ \\   \frac{5t+3t-3}{ t^{2}-t } 
 \\ \\   \frac{8t-3}{ t^{2}-t }
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