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Usimov [2.4K]
2 years ago
15

Help on questions 11 and 15 Add and simplify if possible

Mathematics
2 answers:
Svetllana [295]2 years ago
7 0
\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}
nika2105 [10]2 years ago
4 0
\frac{16+x}{x^{3} } +  \frac{7-4x}{ x^{3} } 
 \\ 16+x+7-4x = 23-3x
 \\  \frac{23 -3x}{ x^{3} }
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\frac{5}{t-1}  +\frac{3}{t} 
  \\ \\  \frac{5t+(t-1)(3)}{(t-1)(t)} 
 \\ \\   \frac{5t+3t-3}{ t^{2}-t } 
 \\ \\   \frac{8t-3}{ t^{2}-t }
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Help me with this one problem please :( <br> Find the following arc measures.
r-ruslan [8.4K]

Answer:

Arc KL =23

Arc OM =113

Step-by-step explanation:

We know that Angle NPM is equal to 90 degrees.

Therefore, Angle KPM is also equal to 90 degrees.

We are told that Arc LM is equal to 67.

Thus, the measure for Arc KL is equal to 90-67=23

We also know that Angle OPN is equal to Angle KPL.

Therefore, the measure of Arc ON=23

Using that information, we know that Arc OM is equal to 90+23=113

Hope I helped!

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