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3 years ago

What is the degree of the polynomial 5a^6bc^2+8d^5+7e^6f^2-10g^4h^7

Mathematics

1 answer:

defon3 years ago

6 0

Answer:

Explanation:

Add all of the exponents together to get the degree of the polynomial.

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How many triangles can be constructed with side lengths 5, 7, and 15?

IrinaVladis [17]

More than ne triangle

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3 years ago

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15 + r as a verbal expression

kodGreya [7K]

Hey there!

<h2>ANSWER: $r+15$ </h2><h2>EXPLANATION:</h2><h2> $15+r$ </h2>

Simplify by flipping.

$r+15$

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3 years ago

What is the greatest common factor GCF of 10 and four

Pani-rosa [81]

Answer:

Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

Step-by-step explanation:

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3 years ago

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Eduardo has a recipe that uses 2/3 cup of flour for each batch. If he makes 4 batches, how many cups of flour will he need? How

34kurt

Answer:

4 batches: $2\frac{2}{3}$ cups

7 batches: $4\frac{2}{3}$ cups

Step-by-step explanation:

If he uses 2/3 cup of flour for <u>each</u> batch, then that is 2/3 four times, or 2/3 · 4.

$\frac{2}{3}$ × $\frac{4}{1}$

= $\frac{8}{3}$ = $2\frac{2}{3}$

If he makes three more, than that will be 7 batches in total. We can multiply 2/3 by 3 to find out how much will be needed for those extra three, then add that product to $2\frac{2}{3}$ .

$\frac{2}{3}$ × $\frac{3}{1}$

= $\frac{6}{3}$ = 2

$2\frac{2}{3} +2$ = $4\frac{2}{3}$

Thus, $2\frac{2}{3}$ and $4\frac{2}{3}$ are the answers.

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2 years ago

The half-life of cesium-137 is 30 years. Suppose we have a

VMariaS [17]

(a) If $y(t)$ is the mass (in mg) remaining after $t$ years, then $y(t) = y(0) e^{kt}=100e^{kt}.$

$y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\
y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}$

(b) $y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}$

(c)
$100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\
t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}$

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3 years ago