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gladu [14]
3 years ago
9

For options A– E choose all of the expressions that are equivalent to 3(4x + 3).

Mathematics
1 answer:
Katen [24]3 years ago
3 0
3(4x+3) = 12x + 9
A= 3(4x+1)
B= 9 + 12x
C= 7x + 6
D= 12x + 9
E= 12x + 9

Answer: D, E

Hope This Helps✨
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HELP ASAP (show work please)
adelina 88 [10]
180= x+24+6x+18+2x+30
180= 9x+72
108=9x
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8 0
3 years ago
HELP ME (How many cubes with side length 1/2 cm does it take to fill the prism
Natalija [7]

answer:

6

step-by-step explanation:

  • for this you would find the volume and then divide by 1/2

v = l x w x h

v = (1)(2)(3/2)

v = 3

  • now, divide

3 ÷ 1/2 = 6

  • therefore, it will take 6 half cubes to fill up the container
8 0
3 years ago
Which pair of triangles can be proven congruent by AAS theorem?
lana66690 [7]

I think the answer is D.

3 0
3 years ago
Which of these equations, when solved, gives a different value of x than the other three? 9.1 = -0.2x + 10 10 = 9.1 + 0.2x 10 –
garik1379 [7]

Given:

Different equations are given.

Rhyan paid using a gift card that had $22.20 on it. After the sale, Rhyan's gift card had $1.90 remaining.

To find:

The equation which gives a different value of x than the other three.

To find the equations that could you use to find the price of one tire patch.

Solution:

In option A,

9.1 = -0.2x + 10

0.2x= 10-9.1

0.2x= 0.9

Divide both sides by 0.2.

x=\dfrac{0.9}{0.2}

x=4.5

Similarly,

In option B,

10 = 9.1 + 0.2x

0.9= 0.2x

4.5=x

In option C,

10-0.2x = 9.1

-0.2x = -0.9

x = 4.5

In option D,

9.1 – 10 = 0.2x

-0.9 = 0.2x

-4.5 = x

Since option D has difference solution, therefore the correct option is D.

Let price of one tire patch be x.

So, price of 4 tire patches = 4x

Remaining amount in Rhyan's gift card = $1.90

Total amount = $22.20

Price of 4 tire patches + Remaining amount in gift card = Total amount

4x+1.9=22.2

It can be written as

4x-22.2=-1.9,1.9=22.2-4x,22.2-4x=1.9

Therefore, the correct options are C and E.

4 0
3 years ago
Read 2 more answers
URGENT! PLEASE help me! Full solutions please, and no nonsense answers.
valentinak56 [21]

Answer:

\frac{1}{3x+52}

Step-by-step explanation:

Given

\frac{\frac{1}{x^2+51x+50} }{\frac{2}{x+50}+\frac{1}{x+1}  }

= \frac{\frac{1}{(x+50)(x+1)} }{\frac{2(x+1)+x+50}{(x+50)(x+1)} }

= \frac{1}{(x+50)(x+1)} × \frac{(x+50)(x+1)}{2x+2+x+50} ← cancel (x + 50)(x + 1) on numerator/denominator

= \frac{1}{3x+52}

8 0
3 years ago
Read 2 more answers
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