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OLEGan [10]
3 years ago
14

What is the answer to (y+2y-6)+(2y-4)

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0
You FOIL (First, Outer, Inner, Last)
If you FOIL, you should get 2y^2 - 4y + 4y^2 - 8y +12y -24
Aneli [31]3 years ago
4 0
(y + 2y - 6) + (2y - 4)

1. Substitute '1' for 'y'

(1y + 2y - 6) + (2y - 4)

3y - 6 + 2y - 4

2. Combine like terms

3y + 2y - 6 + 4

Answer: 5y - 10
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Let $$X_1, X_2, ...X_n$$ be uniformly distributed on the interval 0 to a. Recall that the maximum likelihood estimator of a is $
Solnce55 [7]

Answer:

a) \hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

b) E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

c) P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

e) On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

Step-by-step explanation:

Part a

For this case we are assuming X_1, X_2 , ..., X_n \sim U(0,a)

And we are are ssuming the following estimator:

\hat a = max(X_i)  

For this case the value for \hat a is always smaller than the value of a, assuming X_i \sim Unif[0,a] So then for this case it cannot be unbiased because an unbiased estimator satisfy this property:

E(a) - a= 0 and that's not our case.

Part b

For this case we assume that the estimator is given by:

E(\hat a) = \frac{na}{n+1}

And using the definition of bias we have this:

E(\hat a) - a= \frac{na}{n+1} - a = \frac{na -an -a}{n+1}= \frac{-a}{n+1}

Since is a negative value we can conclude that underestimate the real value a.

And when we take the limit when n tend to infinity we got that the bias tend to 0.

\lim_{ n \to\infty} -\frac{1}{n+1}= 0

Part c

For this case we the followng random variable Y = max (X_i) and we can find the cumulative distribution function like this:

P(Y \leq y) = P(max(X_i) \leq y) = P(X_1 \leq y, X_2 \leq y, ..., X_n\leq y)

And assuming independence we have this:

P(Y \leq y) = P(X_1 \leq y) P(X_2 \leq y) .... P(X_n \leq y) = [P(X_1 \leq y)]^n = (\frac{y}{a})^n

Since all the random variables have the same distribution.  

Now we can find the density function derivating the distribution function like this:

f_Y (Y) = n (\frac{y}{a})^{n-1} * \frac{1}{a}= \frac{n}{a^n} y^{n-1} , y \in [0,a]

Now we can find the expected value for the random variable Y and we got this:

E(Y) = \int_{0}^a \frac{n}{a^n} y^n dy = \frac{n}{a^n} \frac{a^{n+1}}{n+1}= \frac{an}{n+1}

And the bias is given by:

E(Y)-a=\frac{an}{n+1} -a=\frac{an-an-a}{n+1}= -\frac{a}{n+1}

And again since the bias is not 0 we have a biased estimator.

Part e

For this case we have two estimators with the following variances:

V(\hat a_1) = \frac{a^2}{3n}

V(\hat a_2) = \frac{a^2}{n(n+2)}

On this case we see that the estimator \hat a_1 is better than \hat a_2 and the reason why is because:

V(\hat a_1) > V(\hat a_2)

\frac{a^2}{3n}> \frac{a^2}{n(n+2)}

n(n+2) = n^2 + 2n > n +2n = 3n and that's satisfied for n>1.

8 0
4 years ago
A to the power of 0 multiply by A to the power of 6
alukav5142 [94]

Answer:

just a

Step-by-step explanation:

because if you do anything times by zero, it is zero.

6 0
3 years ago
Read 2 more answers
The graph of g(x) is the graph of f(x)=x+6 reflected across the x-axis.Which equation describes g?
Mandarinka [93]
Reflected across x axis means y turns to -y, meaning, multiply the whole function by -1

f(x) times -1=-1 times (x+6)=-x-6

A is answer
3 0
3 years ago
The equation of line l is -3y + 4x = 9 . Write the equation of a line that is parallel to line l and passes through the point (-
Elan Coil [88]

Answer: y = 3x/4 + 22

Step-by-step explanation:

The equation of line l is -3y + 4x = 9

-3y + 4x = 9

3y = 4x -9

y = (4x -9)/3= 4x/3 - 3

From the slope-intercept equation,

y = mx +c

Where m= slope

Comparing both equations, we have

m = 4/3

If the new line that parallel to line l, that means they have the same slope

So, slope if new line is 3/4.

Points =(-12, 6)

From y = mx + c

x = -12,y = 6

6= 4/3 × -12 + c

6 = -16 + c

c = 6 + 16 = 22

Therefore

The equation of the line that is parallel to line l and passes through the point (-12,6) ,

y = 3x/4 + 22

7 0
3 years ago
Which statements are true?
Montano1993 [528]
Three of those statements are true. 
The only one that is NOT correct is:
<span>Any quadrilateral with one right angle is a rectangle.


</span>
6 0
3 years ago
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