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Anit [1.1K]
3 years ago
15

Plz find any question plz

Mathematics
1 answer:
BigorU [14]3 years ago
4 0

Q11

Suppose the two numbers are x and y so xy = 3000

the HCF = 10

we know that product of two numbers = product of their HCF and LCM

XY = HCF * LCM

3000 = 10 * LCM

3000/10 = LCM

300 = LCM

Answer 300

Q12 : Let us say second number is x so

product of x and 160 = product of HCF and LCM of ( x and 160 )

160 x = 32 * 1760

x= 32 * 1760 / 160

x= 352

Answer : 352

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Answer:

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3x = -4y + 16  Divide by 3.

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(2w-5)(w+7) so far I got 2w^2 + 9w + ?
FromTheMoon [43]

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=2w2+9w−35

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A man has 33 coins in his pocket, all of which are dimes and quarters. If the total value of his change
kupik [55]

Answer:

Number of dimes = 16

Number of quarters = 17

====================================================

Work Shown:

d = number of dimes

q = number of quarters

d+q = 33 coins total, this solves to d = 33-q

10d = value of all the dimes in cents

25q = value of all the quarters in cents

10d+25q = 585 cents total

--------------

Plug in d = 33-q and solve for q

10d+25q = 585

10(33-q) + 25q = 585

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The man has 17 quarters

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He also has 16 dimes.

--------------

Check:

16 dimes + 17 quarters = 33 coins total

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160 cents + 425 cents = 585 cents

The answer is confirmed.

3 0
3 years ago
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