All categories

3 years ago

Plz find any question plz

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

Q11

Suppose the two numbers are x and y so xy = 3000

the HCF = 10

we know that product of two numbers = product of their HCF and LCM

XY = HCF * LCM

3000 = 10 * LCM

3000/10 = LCM

300 = LCM

Answer 300

Q12 : Let us say second number is x so

product of x and 160 = product of HCF and LCM of ( x and 160 )

160 x = 32 * 1760

x= 32 * 1760 / 160

x= 352

Answer : 352

You might be interested in

Topics in math question

Monica [59]

Answer:24

Step-by-step explanation:

5 0

3 years ago

For a biology assignment, Christopher records the height of a plant

aivan3 [116]

What is your question???

3 0

3 years ago

Laurie says summer is 1 over 4 of the year. Maria says summer is 3 over 12 of the year. Who is correct? explain

nasty-shy [4]

Answer:

Step-by-ste

Oh, oh! This is such a tricky question...

Guess what!

Both of them are correct. Why?

Because if we simplify 3/12, we get 1/4th!

(How do you simplify?)

3/12 = 1/4

Because if we divide both "3" and "12" in 3/12 by 3, we get 1 instead of 3 and 4 instead of 12.

I hope you've got it! ;)

4 0

3 years ago

Read 2 more answers

Compare the strengths and weaknesses of the horizontal and vertical methods for adding and subtracting polynomials. Include comm

mariarad [96]

Each method works diffrently the angles inside them is what matters.

6 0

3 years ago

Read 2 more answers

I GIVE BRAINLIEST PLS HELP

ioda

The answer is 8
Here's why:
${ ( \frac{( {6}^{7}) \times ( {3}^{3}) }{( {6}^{6}) \times ( {3}^{4} ) } )}^{3} = \\ ( \frac{6}{3} ) ^{3} = \\ \frac{216}{27} = 8$
The exponents are subtracted one from another when divided.
$\frac{ a ^{b} }{ {a}^{c} } = {a}^{b - c}$
We can look at the problem this way:
$( \frac{6^{7} }{6 ^{6} } \times \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6} \times {3}^{3 - 4} ) = \\ ({6}^{1} \times {3}^{ - 1} )$
Since we have the power of -1 on the 3, we apply this rule:
${a}^{ - b} = \frac{1}{ {a}^{b} }$
Also this rule because we have the power of 1 on the 6:
${a}^{1} = a$
Then we get this:
$(6 \times \frac{1}{3} )^{3} = ( \frac{6}{3} )^{3}$
We apply the rule:
$( \frac{a}{b}) ^{c} = \frac{ {a}^{c} }{ {b}^{c} }$
We get this:
$\frac{{6}^{3} }{ {3}^{3} } = \frac{216}{27} = 8$

4 0

4 years ago