It is not differentiable at x=1 since the slope of the tangent line as x -> 1 from the right is 1 while the slope of the tangent line as x->1 from the left is -1
Answer:
y = -1x + 0.5
Step-by-step explanation:
First, I plotted the points (-7, 8) and (2, -2). Then, I drew a line connecting the two points. At the point (-7, 8), I went down 2 squares and to the right 2. This would give me a slope of -1. Since the line touches the y-axis at 0.5, this is the y-intercept.
I am not sure about the y-intercept of this equation. If I got this wrong, I am sorry and please let me know. Thank you!
Answer:
<em>The value of y when x has a value of 9 is 18</em>
Step-by-step explanation:
<u>Functions</u>
The variables x and y are said to have a quadratic relationship. That information is not enough to set up a general equation for both variables.
Furthermore, we know that tripling the value of x causes the value of y to be multiplied by 9. That leads us to establish a proportional equation between them, as follows:
Where k is an unknown constant.
Let's use the given point (3,2) to find the value of k:
Solving for k:
The equation is now:
Now find y when x=9:
The value of y when x has a value of 9 is 18
Answer:
1) (6,2) (9,2) (3,8) (3,5)
2) (2,-5) (5,-5) (-1,-11) (-1,-8)
Step-by-step explanation:
For the first question, your reflecting over the x-axis into quadrant I, so you just need to make all the coordinates positive. The numbers stay the same - you just get rid of the negative signs. (6,2) (9,2) (3,8) (3,5)
For the second problem, you subtract 4 from the x-value, and 3 from the y-value.
(6,-2) becomes (2,-5)
(9,-2) becomes (5,-5)
(3,-8) becomes (-1,-11)
(3,-5) becomes (-1,-8)