I think its down 2 left pi/3, but did you get the answer?
To get the answer we have to find number of towers.
If Arturo built 3 sandcastles with 6 towers each we can say that Arturo built
3*6=18 towers
If Paco built 5 sandcastles with 4 towers each we can say that Paco built
5*4=20 towers
20-18=2 - difference between Paco and Arturo
Answer:Arturo made more towers. The difference is 2.
Answer:
width = 6
length = 4
Step-by-step explanation:
perimeter = 2L + 2W
L = W - 2
plug in perimeter:
20 = 2L + 2W
you know the length is 2 less than the width
plug in (w - 2) for L:
20 = 2(w - 2) + 2w
solve for w:
20 = 2w - 4 + 2w
20 = 4w - 4
4w = 24
w = 6
now plug in 6 for w in either equation, whichever is easier to solve:
L = 6 - 2
L = 4
width = 6
length = 4
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
There You Make Sure You Leave A Thanks
