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spin [16.1K]
3 years ago
13

I need help plizzzzz

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
Try this dude i hope it is right
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What is the value of k?
sammy [17]

Answer:

I think the answer is 2.. I'm sorry if its incorrect.

Step-by-step explanation:

4 0
3 years ago
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How do you find unit rates
Y_Kistochka [10]

To find unit rates with money divide the price by the amount.

7 0
3 years ago
There are 40 girls and 60 boys in the math club the coach wants to divide the entire club into teams where each team has the sam
lapo4ka [179]
40 and 60
40 = 20 x 2
60 = 20 x 3

GCF = 20

<span>the greatest number of teams coach can make is 20
each team can have 2 girls and 3 boys</span>
6 0
3 years ago
Solve the inequality<br> 3 + 9x &gt;4(x+7)<br> pls help
alexandr402 [8]

Answer:

x<5

Step-by-step explanation:

the greater sign will firstly be changed to = for better solving so we obtain

3+9x=4(x+7)by opening bracket

3+9x=4x+28

9x-4x=28-3

5x=25

divide all through by 5x

we obtain

x=5

the greater sign change here

which is x<5

8 0
3 years ago
HELP PLEASE!!!!!!!!!!!!
Bogdan [553]

Answer:

See the explanation.

Step-by-step explanation:

We are given the function f(x) = x² + 2x - 5

Zeros :

If f(x) = 0 i.e. x² + 2x - 5 = 0

The left hand side can not be factorized. Hence, use Sridhar Acharya formula and  

x= \frac{-2+\sqrt{2^{2}-4\times(-5)\times1 } }{2} and  

x= \frac{-2-\sqrt{2^{2}-4\times(-5)\times1 } }{2}

⇒ x = -3.45 and 1.45

Y- intercept :

Putting x = 0, we get, f(x) = - 5, Hence, y-intercept is -5.

Maximum point :

Not defined

Minimum point:  

The equation can be expressed as (x + 1)² = (y + 5)

This is an equation of parabola having the vertex at (-1,-5) and axis parallel to + y-axis

Therefore, the minimum point is (-1,-5)

Domain :  

x can be any real number

Range:  

f(x) ≥ - 6

Interval of increase:

Since this is a parabola having the vertex at (-1,-5) and axis parallel to + y-axis.

Therefore, interval of increase is +∞ > x > -1

Interval of decrease:

-∞ < x < -1

End behavior :  

f(x) = x^{2} +2x-5 =x^{2}  (1+\frac{2}{x} -\frac{5}{x^{2} } )

So, as x tends to +∞ , then f(x) tends to +∞

And as x tends to -∞, then f(x) tends to +∞. (Answer)

7 0
3 years ago
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