Answer:
x = 12
Step-by-step explanation:
Solve for x:
360 - 30 x = 0
Subtract 360 from both sides:
(360 - 360) - 30 x = -360
360 - 360 = 0:
-30 x = -360
Divide both sides of -30 x = -360 by -30:
(-30 x)/(-30) = (-360)/(-30)
(-30)/(-30) = 1:
x = (-360)/(-30)
The gcd of 360 and -30 is 30, so (-360)/(-30) = (-(30×12))/(30 (-1)) = 30/30×(-12)/(-1) = (-12)/(-1):
x = (-12)/(-1)
(-12)/(-1) = (-1)/(-1)×12 = 12:
Answer: x = 12
With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)
On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4).
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With that in mind, we have the following answers
1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint
2) Continuous data. Like time values, temperatures can be averaged as well.
3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.
4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds.
5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
|x|=absoulte value of x which means whatever x is, make it positive
so first solve any division/multiplication
the only one is 12/46=6/23
so we do the absoulte value signs
-3+45-(-14)
-(-14)=+14
-3+45+14=56
absoulute value of 56=56
56+(-|-87+6/23|)
-87+6/23=-86 and 17/23
absoulte value of -86 and 17/23=86 and 17/23
there is a negative sign in front of the absoulte vaulue so make it negative
56-86 and 17/23=-30 and 17/23 or about -30.73913
To find the answer to this, we can use the formula for the diagonal of a square,
a
, with a being the length of the side. That meaans that the length of the diagonal is 98, which is approximately equal to 138.59.
