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mafiozo [28]
3 years ago
13

The height of a building is

Mathematics
1 answer:
eduard3 years ago
6 0

Answer:

10 feet

Step-by-step explanation:

This is a problem of scale

where scale is

actual height of any object/ height of that object on drawing

given

actual height = 24 feet

this is represented 1/2 inch on drawing

thus

scale = actual height/ height on drawing = 24 feet/1/2 inch = 24*2 feet/ 1 inch

scale = 48 feet / 1 inch

given actual  height of a building = 480 feet

let the height on drawing be x inch

thus

48 feet / 1 inch = 480 feet/ x inch

=> x inch/ 1 inch = 480 feet / 48 feet

=> x = 10 feet

Thus,  the  height of  building on the drawing is 10 feet

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Answer is AAAAAAAAAAAA

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What is the input to a trigonometric function? A ratio, the x position of a point of the circle, a central angle of a circle or
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hat is the input to a trigonometric function? A ratio, the x position of a point of the circle, a central angle of a circle or the y position of a point on the circle

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3 years ago
When the volume of a gas is
Fudgin [204]

Answer: The initial volume is 593.76mL

Step-by-step explanation:

As you do not say anithing about the pressure, i guess that the pressure remains constant.

If the gas is an ideal gas, we have:

P*V = n*R*T

where P is pressure, n is number of moles and R is a constant.

Now, initially we have:

P*Vi = n*R*315°C

finally we have:

P*825mL = n*R*452°C

Now we can take the quiotient of those two equations and get:

(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)

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Vi/852mL = 315/452

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Exercise 11.21) Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad ba
stiv31 [10]

Answer:

Step-by-step explanation:

Hello!

The researcher suspects that the battery life between charges for the Motorola Droid Razr Max differs if its primary use is talking or if its primary use is for internet applications.

Since the means for talk time usage (20hs) is greater than the mean for internet usage (7hs) the main question is if the variance in hours of usage is also greater when the primary use is talk time.

Be:

X₁: Battery duration between charges when the primary usage of the phone is talking. (hs)

n₁= 12

X[bar]₁= 20.50 hs

S₁²= 199.76hs² (S₁= 14.13hs)

X₂: Battery duration between charges when the primary usage of the phone is internet applications.

n₂= 10

X[bar]₂= 8.50

S₂²= 33.29hs² (S₂= 5.77hs)

Assuming that both variables have a normal distribution X₁~N(μ₁;σ₁²) and X₂~N(μ₂; σ₂²)

The parameters of interest are σ₁² and σ₂²

a) They want to test if the population variance of the duration time of the battery when the primary usage is for talking is greater than the population variance of the duration time of the battery when the primary usage is for internet applications. Symbolically: σ₁² > σ₂² or since the test to do is a variance ratio: σ₁²/σ₂² > 1

The hypotheses are:

H₀: σ₁²/σ₂² ≤ 1

H₁: σ₁²/σ₂² > 1

There is no level of significance listed so I've chosen α: 0.05

b) I've already calculated the sample standard deviations using a software, just in case I'll show you how to calculate them by hand:

S²= \frac{1}{n-1}*[∑X²-(∑X)²/n]

For the first sample:

n₁= 12; ∑X₁= 246; ∑X₁²= 7240.36

S₁²= \frac{1}{11}*[7240.36-(246)²/12]= 199.76hs²

S₁=√S₁²=√199.76= 14.1336 ≅ 14.13hs

For the second sample:

n₂= 10; ∑X₂= 85; ∑X₂²= 1022.12

S₂²= \frac{1}{9}*[1022.12-(85)²/10]= 33.2911hs²

S₂=√S₂²=√33.2911= 5.7698 ≅ 5.77hs

c)

For this hypothesis test, the statistic to use is a Snedecors F:

F= \frac{S_1^2}{S_2^2} *\frac{Sigma_1^2}{Sigma_2^2} ~~F_{n_1-1;n_2-1}

This test is one-tailed right, wich means that you'll reject the null hypothesis to big values of F:

F_{n_1-1;n_2-1; 1-\alpha }= F_{11;9;0.95}= 3.10

The rejection region is then F ≥ 3.10

F_{H_0}= \frac{199.76}{33.29} * 1= 6.0006

p-value: 0.006

Considering that the p-value is less than the level of significance, the decision is to reject the null hypothesis.

Then at a 5% level, there is significant evidence to conclude that the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for talk is greater than the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for internet applications.

I hope this helps!

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