The temperature of the compound will follow this function: 1/8x^2+15 ( I could be wrong).
But how did I come up with this function ??
The standard of a quadratic equation is given...the x is given...the f(x) is given. Now plug these in correspondence to find the constants. The rest is algebra. If you are not getting this answer, let me see your work
Use the distributive formula
a(b - c) = ab - ac
statements 1, 3, 4 are correct
Simplify the following:
((-1^3)/(-3)^(-3))^2
1^3 = 1:
((-1)/(-3)^(-3))^2
(-3)^(-3) = 1/(-1)^3×1/3^3 = (-1)/3^3:
((-1)/((-1)/3^3))^2
3^3 = 3×3^2:
((-1)/(-1/(3×3^2)))^2
3^2 = 9:
((-1)/((-1)/(3×9)))^2
3×9 = 27:
((-1)/((-1)/27))^2
Multiply the numerator of (-1)/((-1)/27) by the reciprocal of the denominator. (-1)/((-1)/27) = (-27)/(-1):
((-27)/(-1))^2
(-27)/(-1) = (-1)/(-1)×27 = 27:
27^2
| 2 | 7
× | 2 | 7
1 | 8 | 9
5 | 4 | 0
7 | 2 | 9:
Answer: 729 = 1/729 thus c: is your Answer
Rule: y= 3 • x + 1
Explanation
You times a the number shy three then add one
