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Artist 52 [7]
3 years ago
6

Nish Corporation has provided the following data for the month of April:

Business
1 answer:
Fittoniya [83]3 years ago
4 0

Answer:

Required 1

Schedule of Cost of Goods Manufactured

Raw Materials Cost                                               $41,000

Direct labor cost                                                   $23,000

Manufacturing overhead cost                             $59,000

Add Opening Work in process Inventory            $18,000

Less Closing Work in process Inventory           ($22,000)

Cost of Goods Manufactured                             $119,000

Required 2

Income Statement  for April.

Sales                                                                   $220,000

Less Cost of Goods Sold                                  ($132,000)

Gross Profit                                                          $88,000

Less Expenses

Selling expense                           ($18,000 )

Administrative expense              ($43,000)       ($61,000)

Net Income / (Loss)                                              $27,000

Explanation:

<u>Determination of Raw Materials Cost in Production</u>

Raw Materials T - Account

Debit :

Beginning Balance                                      $26,000

Raw materials purchases                            $50,000

Totals                                                            $76,000

Credit :

Ending Balance                                           $35,000

Work In Process (Balancing figure)             $41,000

Totals                                                            $76,000    

<u>Determination of Cost of Goods Sold</u>

Finished Goods Inventory T - Account

Debit :

Beginning  Finished goods Inventory                $42,000

Cost of Goods Manufactured                             $119,000

Totals                                                                    $161,000

Credit:

Ending Finished goods Inventory                      $29,000

Trading Account (Balancing figure)                   $132,000

Totals                                                                    $161,000

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babymother [125]

Correct/Complete Question:

Florida has an agreement with some other states which recognizes the similarity in education and experience requirements for licensees. What is the agreement called?

(a) Reciprocity

(b) Mutual recognition

(c) Cooperative licensure

(d) Intrastate licensing

Answer:

B, Mutual recognition

Explanation:

Mutual recognition agreement is an agreement that exists between two or more governments that has all parties agree to recognize each other's assessment results.

As regards the state of Florida in the question, it has mutual recognition agreements with other state(s) in the the area of education and licensing.This means that Florida state has a the process if licensing a real estate agent.

Cheers.

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3 years ago
Sherman, Inc. manufactures chainsaws that sell for $65. Each chainsaw uses $14 in direct materials and $9 in direct labor per un
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Answer: $18

Explanation:

Based on the information,

Sales revenue = $65 × 225 = $14625

Cost of goods sold = (45 × $20) + (1125 × $4) + (225 × $14) + (225 × $9)

= $900 + $4500 + $3150 + $2025

= $10575

Gross profit = Sales revenue - Cost

= $14625 - $10575

= $4050

The gross profit for one chainsaw will be:

= $4050/225

= $18

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3 years ago
Which statement accurately describes a developing country?The country's population has a high growth rate.The country has a high
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Answer:

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Answer:

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3 years ago
The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

3 0
3 years ago
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