The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
(x, y ) → (x + 11, y - 11 )
Step-by-step explanation:
Consider the point U and its image U'
U (- 9, 1 ) → U' (2, - 10 )
This represents a shift of 2 - (- 9) = 2 + 9 = + 11 → in the x- direction and
- 10 - 1 = - 11 ↓ in the y- direction
This can be shown in the translation rule
(x, y ) → (x + 11, y - 11 )
Answer:
The probability of picking this is 2/7
Step-by-step explanation:
I'm pretty sure this is correct, and my reasoning for this is because there is 1 of most of the letters. This my not be correct, so you should probably try asking someone else, too :D!
Answer:
Step-by-step explanation:
This means that 4/5 repeats itself 3 times.
So,
![\sf = \frac{4}{5} * \frac{4}{5} * \frac{4}{5} \\\\= \frac{64}{125} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%3D%20%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B4%7D%7B5%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B64%7D%7B125%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Can't guess whether you have written 'x' or you have put a sign of multiplication!!
