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egoroff_w [7]
3 years ago
5

Please help !! Will grant brainliest

Mathematics
1 answer:
tamaranim1 [39]3 years ago
4 0

Answer:

6

Step-by-step explanation:

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Pinky Bauer, Chief Financial Officer of Harrison Haulers, Inc., suspects irregularities in the payroll system, and orders an ins
AVprozaik [17]

Answer: 17.89

Step-by-step explanation:

In binomial distribution, the standard deviation is given by :-

\sigma=\sqrt{np(1-p)}

As per given , we have

The number of vouchers in the sample with errors is denoted by x.

p= 0.20  , n = 2000

Then , \sigma=\sqrt{2000\times(0.2)(1-0.2)}

\sigma=\sqrt{320}=17.88854382\approx17.89

Hence, the standard deviation of x is 17.89.

6 0
2 years ago
What is 3.276 x 10^9 in standard form?
Delicious77 [7]

The exponent is a positive number, so you move the decimal point, that many places to the right:

3.276 x 10^9 = 3,276,000,000

7 0
3 years ago
a company promises to release model every month. each model's battery life will be 6% longer than the previous model's. if the c
Ratling [72]

The number of months that it will take the latest model's battery life to reach 1,008.9 minutes is; 8 months

<h3>How to solve geometric progression?</h3>

Each month, there is an increase by a factor of 0.06 of the previous months model.

From geometric sequence formula of aₙ = ar^(n - 1),

where;

a is first term

r is common ratio

aₙ is nth term

we have;

1,008.9 = 671 * 1.06^(n - 1)

1008.9/671 = 1.06^(n - 1)

In 1.504 = (n - 1) In 1.06

0.408 = (n - 1) * 0.058

n - 1 = 0.408/0.058

n = 7.03 + 1

n ≈ 8 months

Read more about geometric sequence at; brainly.com/question/24643676

#SPJ1

5 0
2 years ago
What is the coefficient of q<br> (2/3q-3/4) and -1/6q-r)
kirza4 [7]
The coefficient in (2/3q-3/4) is 2/3 and in (-1/6q-r) is -1/6
4 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0
3 years ago
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