Round 7,248,193,675 to the nearest billion

Mathematics

1 answer:

Art [367]3 years ago

5 0

7 billion is the answer.

You might be interested in

Find the area of the figure

Ostrovityanka [42]

Answer : B

Step by step: make it into two shapes by drawing a line through the shape which would be a square and a triangle. Area of square is bxh so 8x10=80
Area of triangle is 1/2(bxh) so 1/2(4x5)=10

80+10=90

6 0

2 years ago

Read 2 more answers

Gregory teaches martial arts. He charges a one−time processing fee of $5.00 and the cost of the classes is shown below. Let x re

yKpoI14uk [10]

According to the information given it appears that the first class is $15 and each additional class is $12. one class at $15 + 9 classes at $12 + $5 processing fee = $128

5 0

2 years ago

HELP WILL MARK YOU BRAINLIEST NO GUESSES PLZ!!!!!!!!!!!!

shtirl [24]

Answer:72

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

May someone help me out with this please I seriously need someone to help me

olga2289 [7]

7.0258 daL is the answer daL stands for deka liters

7 0

3 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago