Answer:
3p^3 + qp^2 - pq^2 + 3q^3
Step-by-step explanation:
(p²-pq + q²) ( 3p+ 3q)
3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3
3p^3 + qp^2 - pq^2 + 3q^3
50=3x+b. you never specify the variable that replaces b
Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>
<span>2s+5>= 49
Subtract 5 from both sides
2s>=44
Divide 2 on both sides
Final Answer: s>=22</span>
