<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Answer:
he grows by 5 cm every year between 1999 and 2006
Step-by-step explanation:
This is a arithmetic progression problem with the formula;
T_n = a + (n - 1)d
We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.
Thus;
a = 146
d = 2006 - 1999 = 7
Thus;
176 = 146 + (7 - 1)d
176 - 146 = 6d
30 = 6d
d = 30/6
d = 5 cm
Thus, he grows by 5 cm every year between 1999 and 2006
All together it equals (of the number of hours he does in a week)
45 because 6 plus 9 is 15 and 15 multipled by 3 is 45 makes sense becuase .. 6 +3 is 9 and 9 +9 is 18 2 weeks equals 14 days 18 subtracted by 14 equals 2 which 45 subtracted by 2 is 43 and that's the esact number of hours he works 43 in a week.
3.01 is the decimal notation for 3 1/100. You keep the three in the ones place. 1/100 is a decimal. If you use long division or a calculator, you can see that 1/100 is 0.01.
Answer:
Um what is the question on the test?
