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2 years ago

14

Please help me..please

1 answer:

myrzilka [38]2 years ago

6 0

Why are you asking me for help

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Plz help me!!!!!!!!!!!!!!!!!! all 3 problems plz

tensa zangetsu [6.8K]

Answer:

1) 47, 48,49

2) the slope is -3

3) slope is 8

Step-by-step explanation:

for the first one, another person already gave you the answer. For the second one, do y1-y2 over x1-x2. For the third one, move 8x to the other side, and 8 is the slope

4 0

2 years ago

Can a rectangle be a rhombus explain

oksian1 [2.3K]

Yes

But it must be a square since it has to follow the properties of both a rectangle and rhombus.

Also look to find the properties of them to verify yourself

8 0

2 years ago

The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a la

stira [4]

<h2>Answer with explanation:-</h2>

Let $\mu$ be the population mean .

By observing the given information, we have :-

$H_0:\mu=7450\\\\H_a:\mu\neq7450$

Since the alternative hypotheses is two tailed so the test is a two-tailed test.

We assume that the life of a large shipment of CFLs is normally distributed.

(a) Given : Sample size : n=81 , since n>30 so we use z-test.

Sample mean : $\overline{x}=7240$

Standard deviation : $\sigma=1350$

Test statistic for population mean :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

$\Rightarrow\ z=\dfrac{7240-7450}{\dfrac{1350}{\sqrt{81}}}\\\\\Rightarrow\ z=-1.4$

The critical value (two-tailed) corresponds to the given significance level :-

$z_{\alpha/2}=z_{0.025}=1.96$

Since the observed value of z (-1.4) is less than the critical value (1.96) , so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to accept that the mean life is different from 7450 hours .

(b) The p-value : $2P(z>-1.4)=0.1615$ , it means that the probability that the life of CFLs less than 7240 and greater than 7240 is 0.1615.

(c) The confidence interval for population mean is given by :-

$\overline{x} \pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=7240\pm(1.96)\dfrac{1350}{\sqrt{81}}\\\\=7240\pm294\\\\=(6946,7534)$

,

8 0

2 years ago

How do I solve this

NemiM [27]

Old - new is 1 so than after that it would be 1/5 than 1/5 x 100 = 20%

6 0

2 years ago

If a coin is flipped 5 times and a head comes up 2 times, what is the relative frequency of a head coming up?

Rainbow [258]

Answer: I think it's B but i might be wrong

8 0

2 years ago