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Georgia [21]
4 years ago
14

In a probability sample, every element in the population has a(n) ________ chance of being included in the sample.

Mathematics
1 answer:
trasher [3.6K]4 years ago
6 0
The awnser would be possible
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$10.50 an hour

Step-by-step explanation:

210/20 = 10.5

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Rewrite the equation using the properties of exponents. <br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81y%5E7%7D"
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Rewrite the expression without parentheses.<br> 13m−​(−9m−4​)
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22m+4

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
4 years ago
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