First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
2/5
Step-by-step explanation:
C is at the second tick of 6 segements, so C = 2/6 = 1/3.
If we convert all fractions to /60, you can easily see the answer:
1/3 = 20/60
2/5 = 24/60
1/4 = 15/60
1/5 = 12/60
So we're looking for an answer larger than 20/60, which is only 24/60, a.k.a. 2/5.
Enrolement increased by 30% that means last year=100%
incease of 30%=30+100=130% now
now=182
percent means parts out of 100 so
130%=130/100=13/10
182=13/10 of x (x represents the number last year)
of means multipy so
182=13/10 times x
multiply both sides by 10/13 to clear fraction
182 times 10/13=x=140
140 students last year
Box 1) (LxW) 20x6=120
box 2) (LxW) 15x4=60
box 1 cost) (size of box x price of box) 120x1.25=150
box 2 cost) (size of box x price of box) 60x1.25=75
subtract 150 and 75 to get 75
answer: the company is saving $75 by choosing to make 50 of box 2 instead of 50 of box 1
hope this makes sense comment if you need more explanation
