1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry [639]
3 years ago
11

what function is represented below? graph begins in the first quadrant and decreases quickly while crossing the ordered pair

Mathematics
2 answers:
posledela3 years ago
8 0
Hi my name is bubs I need sine money plz help
olchik [2.2K]3 years ago
8 0

Answer:

बूप बीप बूप मैं एक रोबोट हूं जो आपकी सभ्यता को संभालने के लिए आता है! मैं भी पार्ट मार्टियन हूं।

Step-by-Step Explanation:

भाई मेरे पास वास्तव में कोई स्पष्टीकरण नहीं है, लेकिन मॉड शायद इस का अनुवाद नहीं।

You might be interested in
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
2 years ago
What is the answer please ??
dmitriy555 [2]
To solve this, you plug in the first value (3) for x in the equations and and the second value (-6) for y in the equations! if the two equations then equal each other, it is true! if not, it’s false
6 0
2 years ago
Read 2 more answers
A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
Alika [10]

As the ladder is pulled away from the wall, the area and the height with the

wall are decreasing while the angle formed with the wall increases.

The correct response are;

  • (a) The velocity of the top of the ladder = <u>1.5 m/s downwards</u>

<u />

  • (b) The rate the area formed by the ladder is changing is approximately <u>-75.29 ft.²/sec</u>

<u />

  • (c) The rate at which the angle formed with the wall is changing is approximately <u>0.286 rad/sec</u>.

Reasons:

The given parameter are;

Length of the ladder, <em>l</em> = 25 feet

Rate at which the base of the ladder is pulled, \displaystyle \frac{dx}{dt} = 2 feet per second

(a) Let <em>y</em> represent the height of the ladder on the wall, by chain rule of differentiation, we have;

\displaystyle \frac{dy}{dt} = \mathbf{\frac{dy}{dx} \times \frac{dx}{dt}}

25² = x² + y²

y = √(25² - x²)

\displaystyle \frac{dy}{dx} = \frac{d}{dx} \sqrt{25^2 - x^2} = \frac{x \cdot \sqrt{625-x^2}  }{x^2- 625}

Which gives;

\displaystyle \frac{dy}{dt} = \frac{x \cdot \sqrt{625-x^2}  }{x^2- 625}\times \frac{dx}{dt} =  \frac{x \cdot \sqrt{625-x^2}  }{x^2- 625}\times2

\displaystyle \frac{dy}{dt} =  \mathbf{ \frac{x \cdot \sqrt{625-x^2}  }{x^2- 625}\times2}

When x = 15, we get;

\displaystyle \frac{dy}{dt} =   \frac{15 \times \sqrt{625-15^2}  }{15^2- 625}\times2 = \mathbf{-1.5}

The velocity of the top of the ladder = <u>1.5 m/s downwards</u>

When x = 20, we get;

\displaystyle \frac{dy}{dt} =   \frac{20 \times \sqrt{625-20^2}  }{20^2- 625}\times2 = -\frac{8}{3} = -2.\overline 6

The velocity of the top of the ladder = \underline{-2.\overline{6} \ m/s \ downwards}

When x = 24, we get;

\displaystyle \frac{dy}{dt} =   \frac{24 \times \sqrt{625-24^2}  }{24^2- 625}\times2 = \mathbf{-\frac{48}{7}}  \approx -6.86

The velocity of the top of the ladder ≈ <u>-6.86 m/s downwards</u>

(b) \displaystyle The \ area\ of \ the \ triangle, \ A =\mathbf{\frac{1}{2} \cdot x \cdot y}

Therefore;

\displaystyle The \ area\ A =\frac{1}{2} \cdot x \cdot \sqrt{25^2 - x^2}

\displaystyle \frac{dA}{dx} = \frac{d}{dx} \left (\frac{1}{2} \cdot x \cdot \sqrt{25^2 - x^2}\right) = \mathbf{\frac{(2 \cdot x^2- 625)\cdot \sqrt{625-x^2} }{2\cdot x^2 - 1250}}

\displaystyle \frac{dA}{dt} = \mathbf{ \frac{dA}{dx} \times \frac{dx}{dt}}

Therefore;

\displaystyle \frac{dA}{dt} =  \frac{(2 \cdot x^2- 625)\cdot \sqrt{625-x^2} }{2\cdot x^2 - 1250} \times 2

When the ladder is 24 feet from the wall, we have;

x = 24

\displaystyle \frac{dA}{dt} =  \frac{(2 \times 24^2- 625)\cdot \sqrt{625-24^2} }{2\times 24^2 - 1250} \times 2 \approx \mathbf{ -75.29}

The rate the area formed by the ladder is changing, \displaystyle \frac{dA}{dt} ≈ <u>-75.29 ft.²/sec</u>

(c) From trigonometric ratios, we have;

\displaystyle sin(\theta) = \frac{x}{25}

\displaystyle \theta = \mathbf{arcsin \left(\frac{x}{25} \right)}

\displaystyle \frac{d \theta}{dt}  = \frac{d \theta}{dx} \times \frac{dx}{dt}

\displaystyle\frac{d \theta}{dx}  = \frac{d}{dx} \left(arcsin \left(\frac{x}{25} \right) \right) = \mathbf{ -\frac{\sqrt{625-x^2} }{x^2 - 625}}

Which gives;

\displaystyle \frac{d \theta}{dt}  =  -\frac{\sqrt{625-x^2} }{x^2 - 625}\times \frac{dx}{dt}= \mathbf{ -\frac{\sqrt{625-x^2} }{x^2 - 625} \times 2}

When x = 24 feet, we have;

\displaystyle \frac{d \theta}{dt} =  -\frac{\sqrt{625-24^2} }{24^2 - 625} \times 2 \approx \mathbf{ 0.286}

Rate at which the angle between the ladder and the wall of the house is changing when the base of the ladder is 24 feet from the wall is \displaystyle \frac{d \theta}{dt} ≈ <u>0.286 rad/sec</u>

Learn more about the chain rule of differentiation here:

brainly.com/question/20433457

3 0
2 years ago
The hypotenuse of a triangle is 30 cm long and the length of leg A is 15 cm. How long is leg B? (round the the nearest tenth) PL
makvit [3.9K]

Answer:about 26

Step-by-step explanation:

30^2-15^2

Square root it 25.98 about 26

3 0
3 years ago
In circle O below, what is the measure of arc ED?
Serga [27]
Triangle FOD is an isosceles with base FD.
FD = 2 · 4 = 8
FD = CB
Arc CB = 56°
Arc ED = 1/2 Arc FD = 1/2 Arc CB
Arc ED = 56° : 2
Answer:
Arc ED = 28° 

5 0
2 years ago
Other questions:
  • What partial products can you use to find how much 6 bags of cat food will cost
    11·1 answer
  • Plz help with this math problem
    5·2 answers
  • A cross country runner Covers 2.5 miles in 12.5 minutes what is the runners average speed in miles per hour
    7·2 answers
  • The number 4 is the smallest positive integer that has exactly three factors: 1, 2, and 4. If k is the next-highest integer that
    11·1 answer
  • Printer A prints 36 pages every 1.5 minutes. Printer b prints 114 pages every 3 minutes printer c prints 115 pages every 5 minut
    11·1 answer
  • One manufacturer boxes screws so that each box weighs the same no matter what size the screws are. The graph shows the amount of
    6·1 answer
  • Katie has $7 in a savings account. The interest rate is 5%, compounded annually.
    9·2 answers
  • Find the diameter of a circle if its area is<br>a. 100cm2<br>Ibucm2<br>c. 400mcm2<br>d. - ncm2<br>4​
    6·1 answer
  • The volume of this rectangular prism is 8 cubic feet. What is the surface area?
    12·2 answers
  • Dont understand this question so can you please help ?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!