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3 years ago

Quadrilateral

Mathematics

2 answers:

sattari [20]3 years ago

7 0

Answer:

See explanation

Step-by-step explanation:

From the question, we understand that the quadrilateral is rotated by 90 degrees about the origin.

The question is incomplete; so, I will give a general explanation.

The rule for 90 degrees rotation about the origin is:

$(x,y) \to (-y,x)$

For instance:

A point (4,6) will become (-6,4) after rotation.

lesya692 [45]3 years ago

5 0

(x,y)>>>>>>>>(-y,-x) is correct

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How do you get why by itself in this equation? 4x+5y=5

Alja [10]

Answer:

first we get y on one side by itself.

4x+5y=5

we'll move x to the other side.

4x-4x+5y=5-4x

simplify.

5y=5-4x

now we get rid of the coefficient on y.

5y/5=(5-4x)/5

simplify.

y=5/5-4x/5

y=1- $\frac{4}{5}x$

The answer is $y=1-\frac{4}{5}x$

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2 years ago

The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea

Gre4nikov [31]

A) zeroes

P(n) = -250 n^2 + 2500n - 5250

Extract common factor:

P(n)= -250 (n^2 - 10n + 21)

Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000

Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000

Maximum profit =1000 at n = 5

C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.

8 0

3 years ago

Anton [14]

Answer:

000

Step-by-step explanation:

000

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3 years ago

Write each equation in slope-intercept form of the equation of a line. Underline the slope and circle the y-intercept in each eq

Alik [6]

Answer:

see below:

Step-by-step explanation:

2y–6=0

a. slope intercept form using y = mx + b

y = 6/2

y = 3

b. slope: use the slope intercept form: y = mx + b

slope = m = 0

c. y-intercept = (0,3)

7 0

3 years ago

[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =

kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = $1-\frac{_{n}^{12}\textrm{P}}{12^2}$

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= $\frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})$

= $0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1$

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0

3 years ago