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Masja [62]
3 years ago
5

Whats 1+5+1+5+1+25x45x65x2,000

Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0

Answer:

146,250,013

Step-by-step explanation:

1 + 5 + 1 + 5 + 1 + 25 x 45 x 65 x 2,000 =

Follow the correct order of operations.

Do multiplications in the order they appear from left to right.

Then do additions in the order they appear from left to right.

= 1 + 5 + 1 + 5 + 1 + 1,125 x 65 x 2,000

= 1 + 5 + 1 + 5 + 1 + 73,125 x 2,000

= 1 + 5 + 1 + 5 + 1 + 146,250,000

= 6 + 1 + 5 + 1 + 146,250,000

= 7 + 5 + 1 + 146,250,000

= 12 + 1 + 146,250,000

= 13 + 146,250,000

= 146,250,013

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In am election, Mrs.Jones received 70% of the 1,500 votes cast. How many votes did Mrs. Jones receive
WARRIOR [948]

Hello!

To calculate how many votes Mrs. Jones had received, you would begin by converting 70% into a decimal, and then multiplying that decimal by the total number of votes.

Remember, all percentages are out of 100. So, 70/100 can be simplified into 7/10. As a decimal, 7/10 would be 0.7.

Next, we multiply 0.7 by the total number of votes, which is 1,500.

0.7 · 1500 = 1050

Therefore, in this election, Mrs. Jones received 1,050 votes out of the total 1,500 votes casted.

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Solve the system of equations.
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4 0
2 years ago
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
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