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Kipish [7]
2 years ago
9

Find the x and y intercepts c) x + 3y - 12=0

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0
To get x intercept:
let y=0,x➖12=0,x=12
so x intercept point (12,0)
To get y intercept:
let x=0,3y➖12=0,y=4
so y intercept point (0,4)
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Solve for x.<br> 13(x-3) = 39<br> X=1<br> X=4<br> x=6<br> x=10
Valentin [98]
13 factored out is 13x - 39 add 39 to both sides it equals 13x=78 and 78 divided by 13 is 6 the anwser is x=6
7 0
2 years ago
I NEED HELP ASAP with this Question PLEASE
alukav5142 [94]

Answer:

answer is b

Step-by-step explanation:

hope it helps!!!

7 0
3 years ago
Preston's vegetable patch is 7 yards wide and 17 yards long. Preston wants to build a fence around the vegetable patch. The fenc
bezimeni [28]

Answer: 238$

Step-by-step explanation: 7 x 17 = 119 mutiply this x 2.00 = 238

6 0
2 years ago
I need help fast .....​
gizmo_the_mogwai [7]

Answer:

(0,6)

Step-by-step explanation:

So x=0, so plug in 0 for x. 5(0) + 6 - (0)^2 = 6

8 0
3 years ago
Can anybody help me on this please I will be giving 15 points..
oksano4ka [1.4K]

Answer:

BC=\sqrt{95}

Angle A (or BAC)=54.31466...

Angle C (or ACB)=35.68533...

Step-by-step explanation:

\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}

BC=\sqrt{12^2-7^2}

\sqrt{12^2-7^2}=\sqrt{95}

\frac{\sqrt{95}}{\sin \left(\angle \:BAC\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:BAC=54.31466

\frac{7}{\sin \left(\angle \:ACB\right)}=\frac{12}{\sin \left(90\right)}\quad :\quad \angle \:ACB=35.68533

4 0
3 years ago
Read 2 more answers
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