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2 years ago

What is the pattern (these are not ratios) 11 to 25, 27 to 41, 43 to 57, 59 to 73,

Mathematics

2 answers:

Virty [35]2 years ago

8 0

Answer:

Each is increasing by 14

Step-by-step explanation:

11+14=25

27+14=41

43+14=57

59+14=73

see

Nuetrik [128]2 years ago

5 0

Answer:

75, 89, 91, 105, 107, 121, 123, 137

Step-by-step explanation:

If you analyze how much each number is increased, you will notice it alternates between adding 2, then adding 14:

11 + 14 = 25.

25 + 2 = 27.

27 + 14 = 41.

41 + 2 = 43.

43 + 14 = 57.

57 + 2 = 59.

59 + 14 = 73.

That means you can simply, finish the pattern, alternating between adding 2 and 14. Then you will get these answers.

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3 years ago

2. The fifth term and eighth terms of a Gp are 80 and 640 respectively find

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2 years ago

There is a store downtown that sells clothes. The owner has his own method of pricing items. A coat costs $20, a hat costs $15,

Lesechka [4]

Answer:

$25

Step-by-step explanation:

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3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

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tatyana61 [14]

Step-by-step explanation:

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Try to understand the rest from the attached picture

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3 years ago

What is the pattern (these are not ratios) 11 to 25, 27 to 41, 43 to 57, 59 to 73, __ __ __ __ __ __ __ __

What is the pattern (these are not ratios) 11 to 25, 27 to 41, 43 to 57, 59 to 73,