Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
C is the answer
Step-by-step explanation:
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Answer:
The roots of equations are as m =
And n =
Step-by-step explanation:
The given quadratic equation is 2 x² + 6 x - 1 = 0
This equation is in form of a x² + b x + c = 0
Let the roots of the equation are ( m , n )
Now , sum of roots = 
And products of roots = 
So, m + n =
= - 3
And m × n = 
Or, (m - n)² = (m + n)² - 4mn
Or, (m - n)² = (-3)² - 4 (
)
Or, (m - n)² = 9 + 2 = 11
I.e m - n = 
Again m + n = - 3 And m - n = 
Solving this two equation
(m + n) + ( m - n) = - 3 + 
I.e 2 m = - 3 + 
Or, m = 
Similarly n =
Hence the roots of equations are as m =
And n =
Answer
Answer:
3⋅f(−4)−3⋅g(−2) = −12f+6g
Step-by-step explanation:
Write the problem as a mathematical expression.
3⋅f(−4)−3⋅g(−2)
Move − 4 to the left of f .
3⋅(−4⋅f)−3⋅(g(−2) )
Multiply−4 by 3.
−12f−3⋅(g(−2) )
Move − 2 to the left of g .
−12f−3⋅(−2⋅g)
and lastly Multiply−2 by −3.
−12f+6g
Hope this helps you out.