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3 years ago

PLS HELP ME I NEED HELP DESPERATELY I ALSO NEEDA SHOW WORK PLS I POSTED THIS QUESTION SM TIMES W OUT NO HELP ME HELP ME

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

6 0

Answer:

x=3

Step-by-step explanation:

The equation for a vertical line is x=a, where a is any value

You plug in the point, and get x = 3

Veronika [31]3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

vertical line mean x always constant

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nata0808 [166]

Answer:

a. (0, -2)

b. (1, -2)

c. (2, -2)

d. (3, -2)

e. (4, -2)

f. The y-value of the coordinate is always -2. The x-value of the coordinate is always what x is stated to equal.

Step-by-step explanation:

Since the linear equation y = -2 doesn't have a slope, it will be shown as a continuous horizontal line along, touching the y-axis at it's -2 unit.

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Jake accumulated $8,000 in credit card debt. If the interest rate is 20% per year and he does not make any payments for 3 years,

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3 years ago

Is 9 + 3 + 6x the simplify expression of 9 - (3 - 6x)?

Vinil7 [7]

E. he did not multiply 3 by -1 correctly

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3 years ago

Ginny Jones receives $624 gross salary biweekly. Her income tax rate is 14%. Her group health plan contribution is $4.25 per pay

barxatty [35]

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3 years ago

When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance

bekas [8.4K]

a) $v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

The average speed is equal to the ratio between the total distance ( $d_{tot}$ and the total time taken ( $t_{tot}$ ):

$v=\frac{d_{tot}}{t_{tot}}$

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

$d_1 = (3 h)(60 mph)=180 mi$

So the total distance is

$d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi$

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

$t_{tot}=3 h +t_2$

So, the equation can be rewritten as:

$v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}$

b) 0.50 h (half a hour)

Since we know the value of the average speed, $v=57.14 mph$ , we can substitute it into the previous equation to find the value of $t_2$ , the time the trucker drove in the city:

$v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h$

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3 years ago