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fiasKO [112]
3 years ago
10

Alejandro has 64-centimeter cubes. He uses them to build cubes with

Mathematics
1 answer:
Greeley [361]3 years ago
7 0

Answer:

7 different cubes

Step-by-step explanation:

Given: Alejandro has 64-centimeter cubes.

We know, cube is three dimentional solid object

Now, using 64 centimeter cubes to build cubes with  different side lengths.

∴ Finding the different possible 3 multiple(dimention) of 64 to know the number of cubes.

64= 64\times 1\times 1

64= 32\times 2\times 1\\64= 16\times 4\times 1\\64= 16\times 2\times 2\\64= 8\times 8\times 1\\64= 8\times 4\times 2\\64= 4\times 4\times 4

Hence, we can have 7 different cubes with 64 cm cubes.

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Given: BAD = CAD. Find the perimeter of ABC.
11111nata11111 [884]

Answer:

34 units

Step-by-step explanation:

Since the triangles are equal, the bottom length of triangle CAD will be the same as the bottom length of BAD. This means that the total length of the bottom of triangle ABC is 6 (3 + 3).

Next, you need to find the length of AC and again, since they're the same triangle, AB will be the same as AC, 14.

The three side lengths of the triangle will be 6, 14, and 14, so the perimeter is

6 + 14 + 14 = 34 units

4 0
3 years ago
the bike course is 80 miles long and I have ridden 44 miles of the course. what percentage have avridden?
andreev551 [17]
You have ridden 55% of the way.

You have to set up a proportion 44 over 80 is equal to x over 100 (x is what we are trying to find - the percentage you have ridden). Then use cross products and multiply the 44 by 100 to get 4400 and divide that by 80 to get 55. So the answer is 55 so 55%.

55%.

Hope this helps!
Can u plz mark me as brainliest? I really need it!
8 0
3 years ago
1. -4(m+2)=-8-4m<br><br> gjkrbegbsrbgrwg
pantera1 [17]
-4m-8=-8-4m
+4 +4
__________
-8=-8
or
1=1
6 0
3 years ago
What is 11 in x 17 in (7.7 in x 23) in
Ad libitum [116K]

33117.7 in is the answer I believe…

5 0
2 years ago
Expand the following using the Binomial Theorem and Pascal’s triangle. (x + 2)6 (x − 4)4 (2x + 3)5 (2x − 3y)4 In the expansion o
ivolga24 [154]
\bf (2x+3)^5\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^5(+3)^0\\&#10;2&+5&(2x)^4(+3)^1\\&#10;3&+10&(2x)^3(+3)^2\\&#10;4&+10&(2x)^2(+3)^3\\&#10;5&+5&(2x)^1(+3)^4\\&#10;6&+1&(2x)^0(+3)^5&#10;\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

so...how did we get 10 for the 3rd element?  well, 5*4/2
how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(2x)^4(-3y)^0\\&#10;2&+4&(2x)^3(-3y)^1\\&#10;3&+6&(2x)^2(-3y)^2\\&#10;4&+4&(2x)^1(-3y)^3\\&#10;5&+1&(2x)^0(-3y)^4&#10;\end{array}


\bf (3a+4b)^8\implies &#10;\begin{array}{llll}&#10;term&coefficient&value\\&#10;-----&-----&-----\\&#10;1&&(3a)^8(+4b)^0\\&#10;2&+8&(3a)^7(+4b)^1\\&#10;3&+28&(3a)^6(+4b)^2\\&#10;4&+56&(3a)^5(+4b)^3\\&#10;5&+70&(3a)^4(+4b)^4\\&#10;6&+56&(3a)^3(+4b)^5\\&#10;7&+28&(3a)^2(+4b)^6\\&#10;8&+8&(3a)^1(+4b)^7\\&#10;9&+1&(3a)^0(+4b)^8&#10;\end{array}

and from there, you can simplify the elements of the expansion by combining the coefficients

like for example, the 7th element of (3a+4b)⁸ will then be 1032192a²b⁶
7 0
3 years ago
Read 2 more answers
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