Solve x2 + 2x =1 for x by completing the square.

Click here What is the average rate of change for this exponential function for the interval from x=2 to x = 4? 15 10 -5 5 10 O

Triss [41]

Answer:

c. 6

Step-by-step explanation:

Given

See attachment for graph

Required

Average rate of change

This is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

Where

$(a,b) = (2,4)$

So, we have:

$Rate = \frac{f(4) - f(2)}{4 - 2}$

$Rate = \frac{f(4) - f(2)}{2}$

Using the attached graph, we have:

$f(2) = 4$

$f(4) = 16$

So, we have:

$Rate = \frac{16- 4}{2}$

$Rate = \frac{12}{2}$

$Rate = 6$

4 0

3 years ago

Katie works at a department store that sells shoes. She receives an employee discount for any shoes she buys at the store. If Ka

exis [7]

Answer:

55-45=10 it's 10$ discount

$\frac{10}{55}*100=18.19\%$

Step-by-step explanation:

8 0

3 years ago

Jake scored 269 points on three math tests. To get an A for the class, his average number of points on four tests must be no les

nadya68 [22]

Jake must score a minimum of a 94%

$269 + 94 = 363 \\ 363 \div 4 = 90.75$

3 0

3 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 3, 1), (0, 3, 1), and back to the origin under

sweet [91]

Answer: Work done by the particle is 78 N.

Step-by-step explanation:

If C is the path the particle follows, then work done is $\int_{C}^{}F.dx$ .

According to the question the force $F=z^{2}i+5xyj+4y^2k$ and all four points are in the plane $z=\frac{1}{4}y$ .

therefore, if S is the at surface with boundary C, so that S is the portion of the plane $z=\frac{1}{4}y$ over the rectangle D=[0,2]\times [0,4].

Now,

$curlF=\begin{vmatrix}i &j &k \\ \frac{\partial }{\partial x}&\frac{\partial }{\partial y} &\frac{\partial }{\partial z} \\ z^{2}&5xy &4y^{2} \end{vmatrix}=8yi+2zj+5yk$

By the Stoke's theorem:

$\int_{C}^{}F.dx=\iint_{s}^{}curlF.dS\\\\=\iint_{D}^{}[-8y(0)-2z\left ( \frac{1}{4} \right )+5y]dA\\\\=\iint_{D}^{}\left ( -\frac{1}{2}z+5y \right )dA$

$=\iint_{D}^{}\left ( \frac{39}{8}y \right )dA\, \, \, \, \, \, \, \, \, Since\, \, z=\frac{1}{4}y\\\\=\int_{0}^{2}\int_{0}^{4}\frac{39}{8}y\, \, \, dy\, dx\\\\$

$\int_{0}^{2}\left [ \frac{39}{16}y^2 \right ]_{0}^{4}dx\\\\=\int_{0}^{2}39\, \, dx\\\\=39\times 2\\\\=78 \, N$

8 0

4 years ago

the front of a podium is in the shape of a trapezoid with base lengths 4 and 8.5 feet. the height is 2 feet. a gallon of paint c

Stels [109]

Podium is in the shape of a trapezoid with base lengths. 4 and 8.5 feet. The height is 2 feet. A gallon of paint covers about. 350 square feet. 1,224 square inches

6 0

3 years ago