D=11/5p-33
11/5p=D+33
p=5/11D+15
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
The slope is steeper and the line is shifted 1 unit down
So I think you’re looking for an outlier not an outliner. An outlier is a piece of data that doesn’t match the trend, like the misfit that doesn’t fit with the rest. For example if I had measurements of 1,2,4,84,3 then 84 would be the outlier. Hope this helps!
There is no solution I believe since 2/3 and 8/10 cross multiplied are 2 times 10 and 3 times 8 which is 20 = 24 which does not equal and there is no answer