Question

A conductor possesses a positive charge of 3.2x 10-19 C. How many electron does it have in excess or deficit (e = 1.60 x 10-19C)

Answer 1

The no of electrons it have in deficit=1.60

Given:

Charge possessed by a conductor = $3.2 \times 10^{-19} C$

Charge of an electron=$1.6 \times 10^{-19} C$

To find:

Amount of electrons in excess or deficit

Step by Step Explanation:

Solution;

Formula used for calculating electrons in excess or deficit is given as

Electrons in excess or deficit= Normal electron charge- Charge of the conductor

Also we know Charge of Conductor$=3.2 \times 10^{-19} C$ and Electron charge$=1.6 \times 10^{-19} C$  

Substitute these values in the above equation we get

Electrons in excess or deficit=$1.60 \times 10^{-19} \mathrm{C}-3.2 \times 10^{-19} \mathrm{C}$

= -1.60

Result:

Hence, it has a deficit of 1.60 electrons.