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dolphi86 [110]
4 years ago
8

H – 1 = 7.2 h= Answer

Mathematics
2 answers:
jok3333 [9.3K]4 years ago
7 0
I don’t understand what do u mean 0.o
soldier1979 [14.2K]4 years ago
7 0

Answer:

Step-by-step explanation:

h - 1 = 7.2

h = 8.2

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tom jogged 3/10 mile, betsy jogged 5/10 mile, and sue jogged 2/10 mile. who jogged a longer distance than 4/10 mile?
Inga [223]
Betsey jogged the longer distance.
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4 years ago
A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is
Virty [35]

Answer:

  • See below

Step-by-step explanation:

<u>The side of the square is w/2, then its area is:</u>

  • A = (w/2)² = w²/4

<u>The shaded area is the difference of areas of the rectangle and the square:</u>

  • 14w - w²/4 = 84

<u>This can be simplified:</u>

  • 56w - w² = 336
  • w² - 56w + 336 = 0

8 0
3 years ago
At a restaurant jars of tomato sauce are stored in boxes in the pantry. Each box contains 8 jars of tomato sauce. A cook uses 2
defon

Answer:

y = 8x − 2

Step-by-step explanation:

x =the number of boxes

Total jars of tomato sauce is each box contains 8 jars so that is 8 x x=8x

2 jars were removed making it 8x-2

y will be 8x-2

3 0
3 years ago
Create an expression that is equivalent to 79.86-17.61
lesya [120]
62.25 + 1 - 1 cause that's just 62.25 + 0 which is 62.25
5 0
3 years ago
Batman (mass=100 kg) jumps straight down from a bridge in to a boat (mass = 580 kg) in which a criminal is fleeing. The velocity
Crank

Answer:

v_b=11.94\ m/s

Step-by-step explanation:

<u>Linear Momentum </u>

The momentum of a system of masses m1,m2,m3... with speeds v1,v2,v3,... is given by

M=m_1v_1+m_2v_2+m_3v_3+...

When some interactions take place into the system of masses with no external forces interferring, the total momentum is not changed, which means that if the new speeds are v1', v2', v3'... then:

m_1v_1+m_2v_2+m_3v_3+...=m_1v_1'+m_2v_2'+m_3v_3'+...

The problem relates the story of Batman (m1=100kg) who is initially assumed at rest and lands on a boat with mass m2=580 kg initially moving at 14 m/s to the positive reference. When the collision takes place, both masses join and a common speed v_b is achieved by the common mass. Applying the conservation of momentum, we have

m_1v_1+m_2v_2=(m_1+m_2)v_b

Since v_1=0

m_2v_2=(m_1+m_2)v_b

Solving for v_b

\displaystyle v_b=\frac{m_2v_2}{m_1+m_2}

\displaystyle v_b=\frac{(580)(14)}{100+580}

\boxed{v_b=11.94\ m/s}

7 0
3 years ago
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