3 years ago

How to expand (3x-4y)^6

1 answer:

4 0

Steps
(3x· 4y)(2x−3y)
Apply the distributive law: a(b−c)=ab−ac
(3x· 4y)(2x−3y)=3x· 4y· 2x−3x· 4y· 3y
=3x· 4y· 2x−3x· 4y· 3y
Show Steps
Simplify 3x· 4y· 2x−3x· 4y· 3y: 24x2y−36xy2
=24x2y−36xy2

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Answer:

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Step-by-step explanation:

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As given in question the nth term in A.P is given by

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$a_{105}=\dfrac{1}{2}+(105-1)\dfrac{1}{2}$

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How to expand (3x-4y)^6 ​

How to expand (3x-4y)^6