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8_murik_8 [283]
3 years ago
7

If m(x) = x3 and n(x) = √ 6 + x , find the function value, if possible.

Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

Answer:

The correct answer is option D.  -126  

Step-by-step explanation:

<u>Points to remember</u>

<u>Composite functions</u>

f(x) and g(x) be the functions then,

(f - g)(x) = f(x) - g(x)

<u>To find the value of (m - n)(-5)</u>

Let  m(x) = x³ and n(x) = √ (6 + x)

(m - n)(x) = m(x) - n(x)

 =  x³ - √( 6 + x)

(m - n)(-5) = m(-5) - n(-5)

 =  x³ - √( 6 + x)

 =  (-5)³ - √( 6 + -5)

 = -125 -  √1

 = -125 -1

 = -126

The correct answer is option D.  -126

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The perimeter of a rectangular garden is 9696 meters. The length is 6 meters longer than twice the width. Find the dimensions of
nalin [4]

length = 3234 m and width = 1614 m

let the width = w then length = 2w + 6

Perimeter = 2 ( length + width )

               = 2 (2w + 6 + w ) = 2 ( 3w + 6 ) = 6w + 12

given perimeter = 9696 the equating gives

6w + 12 = 9696

subtract 12 from both sides

6w = 9696 - 12 = 9684

divide both sides by 6

w = \frac{9684}{6} = 1614

width = 1614 m and length = (2 × 1614 ) + 6 = 3234 m


3 0
4 years ago
Rise over run value?
finlep [7]
Is that all the information given?
6 0
4 years ago
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Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
A location's elevation is measured by its height above or below sea level. Sea level is defined as being at an elevation of 0 me
iragen [17]

Answer:

Got a list?

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
!!!!please help me on 2!!!!​
Kaylis [27]

Answer:

I think it's -5x

Step-by-step explanation:

I'm assuming the zero pair is simply adding

5 0
3 years ago
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