What are the constants in this expressions?-10.6+9/10+2/5m-2.4n+3m
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Answer:
The 't' test statistic = 1.46 < 1.69
The test of hypothesis is H 0 :μ = 800 is accepted
A sample of 30 bulbs are found came from average µ= 800
Step-by-step explanation:
Step 1:-
Given population of mean μ = 800
given size of small sample n =30
sample standard deviation 'S' = 45
Mean value of the sample χ = 788
Null hypothesis µ =800
alternative hypothesis µ ≠ 800
<u>Step 2</u>:-
The 't' test statistic t =
t = = 1.4607
<u>Step 3</u>:-
The degrees of freedom γ = n-1 = 30-1 =29
From "t" value from table at 0.05 level of significance ( t = 1.69)
The calculated value t = 1.4607 < 1.69
Therefore The null hypothesis H_{0} ' is accepted.
<u>conclusion</u>:-
A sample of 30 bulbs are came found from average µ= 800
Input (x-value)
Output (y-value)
You need to find the x-value that produces a y-value of -1. Since you know:
y = -1 Use the rule, and substitute/plug this into the equation
y = -2x + 33 Plug in -1 for "y" in the equation since y = -1
-1 = -2x + 33 Subtract 33 on both sides
-1 - 33 = -2x + 33 - 33
-34 = -2x Divide -2 on both sides to get "x" by itself
17 = x
An input of 17 yields an output of -1