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3 years ago

HELP ME PLEASE!!!!!!! ASAP!!!

Mathematics

1 answer:

Svet_ta [14]3 years ago

6 0

x2+5x+3x-24

x(x+5)+3(x-8)

(x+3)(x+5)

x+3=0orx+5=0

x=-3orx=-5

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Evaluate. Round to the nearest tenth

Dima020 [189]

Apply log rules

$log_b(1) = 0$

So

$log_{12}(1)=0$

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3 years ago

How to put 1+0.9+0.08+0.001 in word form

Svet_ta [14]

1.981: One and nine hundred eighty-one thousandths

6 0

3 years ago

I really need help with this, thank you!!!

Lyrx [107]

Answer:

6. 60°

7. 5.19559

8. 7.96011

Step-by-step explanation:

6. The sum of angles in a triangle is 180°, so the remaining angle is ...

180° -40° -80° = 60°

7. The lengths of sides are proportional to the sine of the opposite angle (Law of Sines).

a = c·sin(A)/sin(C) = 7·sin(40°)/sin(60°) ≈ 5.19559

8. Same explanation as 7.

b = c·sin(B)/sin(C) = 7·sin(80°)/sin(60°) ≈ 7.96011

3 0

3 years ago

Read 2 more answers

A positive number is 1/4 of another positive number. If the difference is 60 find two positive numbers. I need help Pewase

Varvara68 [4.7K]

Answer:

60 1/4

Step-by-step explanation:

x-1/4=60

x=60+1/4

x=60 1/4

3 0

3 years ago

If the cost of an item increased by a percentage and decreased by the same percentage, what would that percentage be if the new

Orlov [11]

The percentage, if the new cost was 84% of the original is 40%

Let the cost of the item be x.

When the price increased by y%, the new price is:

$New =x \times (1 + y\%)$

When the price decreased by the same percentage (i.e. y%), the new price is:

$New =x \times (1 + y\%) \times (1 - y\%)$

The cost is said to be 84% of the original price.

So, we have:

$x \times (1 + y\%) \times (1 - y\%) =84\% \times x$

Divide both sides by x

$(1 + y\%) \times (1 - y\%) =84\%$

Apply the difference of two squares

$1 - (y\%)^2 =84\% \\\\$

Subtract 1 from both sides of the equation

$- (y\%)^2 =-16\%$

Cancel out the common factors

$(y\%)^2 =16\%$

Take the square root of both sides

$y\% =0.4$

Multiply both sides by 100

$y =40$

Hence, the percentage is 40%

Read more about percentage change at:

brainly.com/question/809966

8 0

2 years ago