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olga55 [171]
3 years ago
11

Please help for gods sake:(

Mathematics
2 answers:
worty [1.4K]3 years ago
6 0

Answer:

answer is b)

Step-by-step explanation:

please mark me brainliest

MrRissso [65]3 years ago
5 0

Answer:

The answer is B

Step-by-step explanation:

Mark me

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What number are listed in the stem and leaf plot above
Paul [167]
The numbers listed are:

3, 3 ,3 ,7 ,8 ,8 ,11 ,11 ,13 ,14 ,15 ,17, 18, 19, 21, 23, 23 ,25,27, 28, and 29.
3 0
3 years ago
What is the repeating or terminating decimal that is equivalent to 11/36
Oduvanchick [21]

Answer:

0.30555555....

Step-by-step explanation:

(The fives keep on coming, this is a repeating decimal.)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
2 years ago
What is the midpoint of AB?
BabaBlast [244]

Answer:

A picture of the problem might help

7 0
3 years ago
Type the correct answer in each box. Round your answers to two decimal places. Subtract vector v = &lt;2, -3&gt; from vector u =
expeople1 [14]

u - v = <5, 2> - <2, - 3> = <5 - 2, 2 + 3> = <3, 5>

given a vector <u, v> then the magnitude is √ (u² + v² ) and it's angle of direction is

θ = tan^{-1}(\frac{v}{u})

thus the magnitude of <3, 5> = √(3² + 5²) = √34 ≈ 5.83 ( to 2 dec. places )

Θ = tan^{-1}(\frac{5}{3}) = 59.04° ( to 2 dec. places )



3 0
3 years ago
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