Answer:


Step-by-step explanation:
Given system of equations:

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

Factor the quadratic:

Apply the <u>zero-product property</u> and solve for x:


Substitute the found values of x into the <u>second equation</u> and solve for y:


Therefore, the solutions are:


Anything greater than 1/2 can be shown as >1/2
We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!
We are given with ;
Take LCM on both sides :
<em>Multiplying</em> both sides by <em>10</em> ;

Can be <em>further written</em> as ;
Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>


9. 2.86600.... that is all i know so far