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kakasveta [241]
3 years ago
12

Which of the following is an example of a chemical change?

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
7 0

The answer is B.

To find the answer you can immediately cross out A and C. You're left with a mixture of ingredients that turn into a cake or choclate melting. Chocolate melting is a physical change so by using the process of elimination you can conclude that B is the correct answer.

Mariulka [41]3 years ago
4 0

Answer:

The correct answer is option B.

Step-by-step explanation:

We call chemical change to the process where two or more substances are transformed into other substances.

During this change, the substances will have a modification in the structure of their molecules and their bonds.

In the case of the example we can see how different substances (flour, sugar, eggs and butter) will change the shape of their structure to form another substance: the cake. This cake will receive the name of <em>product</em>.

Given this information, we can say that the correct answer is option B.

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On Wednesday the farmers at the Harrison Farm picked 3/4 of a barrel of tomatoes. Thursday, the farmers picked 4/5 as many tomat
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3/5

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A cylinder has a height of 16 inches and a radius of 17 inches. What is its volume? Use ​ ≈ 3.14 and round your answer to the ne
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Read 2 more answers
If m and n are off then is mn even?
11111nata11111 [884]

Answer:

No, mn is not even if m and n are odd.

If m and n are odd, then mn is odd as well.

==================================================

Proof:

If m is odd, then it is in the form m = 2p+1, where p is some integer.

So if p = 0, then m = 1. If p = 1, then m = 3, and so on.

Similarly, if n is odd then n = 2q+1 for some integer q.

Multiply out m and n using the distribution rule

m*n = (2p+1)*(2q+1)

m*n = 2p(2q+1) + 1(2q+1)

m*n = 4pq+2p+2q+1

m*n = 2( 2pq+p+q) + 1

m*n = 2r + 1

note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.

The result 2r+1 is some other odd number as it fits the form 2*(integer)+1

Therefore, multiplying any two odd numbers will result in some other odd number.

------------------------

Examples:

  • 3*5 = 15
  • 7*9 = 63
  • 11*15 = 165
  • 9*3 = 27

So there is no way to have m*n be even if both m and n are odd.

The general rules are as follows

  • odd * odd = odd
  • even * odd = even
  • even * even = even

The proof of the other two cases would follow a similar line of reasoning as shown above.

4 0
3 years ago
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