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Alexxandr [17]
3 years ago
12

If m and n are off then is mn even?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
4 0

Answer:

No, mn is not even if m and n are odd.

If m and n are odd, then mn is odd as well.

==================================================

Proof:

If m is odd, then it is in the form m = 2p+1, where p is some integer.

So if p = 0, then m = 1. If p = 1, then m = 3, and so on.

Similarly, if n is odd then n = 2q+1 for some integer q.

Multiply out m and n using the distribution rule

m*n = (2p+1)*(2q+1)

m*n = 2p(2q+1) + 1(2q+1)

m*n = 4pq+2p+2q+1

m*n = 2( 2pq+p+q) + 1

m*n = 2r + 1

note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.

The result 2r+1 is some other odd number as it fits the form 2*(integer)+1

Therefore, multiplying any two odd numbers will result in some other odd number.

------------------------

Examples:

  • 3*5 = 15
  • 7*9 = 63
  • 11*15 = 165
  • 9*3 = 27

So there is no way to have m*n be even if both m and n are odd.

The general rules are as follows

  • odd * odd = odd
  • even * odd = even
  • even * even = even

The proof of the other two cases would follow a similar line of reasoning as shown above.

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Answer: 9+d=x or x=9+d

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3 years ago
PLEASE HELPPPPP. URGEENNTT!!! I DONT KNOW HOW TO SOLVE THIS
Oksi-84 [34.3K]

Answer:

A = 58.7 degrees

B = 66.9 degrees

C = 34.1 degrees

Step-by-step explanation:

<u><em>For <A:</em></u>

Tan A = \frac{opposite}{adjacent}

Tan A = \frac{23}{14}

Tan A = 1.6

A = Tan^{-1} 1.6

A = 58.7 degrees

<u>For <B:</u>

Sin B = \frac{opposite}{hypotenuse}

Sin B = \frac{23}{25}

Sin B = 0.92

B = Sin^{-1} 0.92

B = 66.9 degrees

<em><u>For <C:</u></em>

Sin C = \frac{opposite}{hypotenuse}

Sin C = \frac{14}{25}

Sin C = 0.56

C = Sin^{-1}0.56

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6 0
3 years ago
Events A and B are independent. The probability of A given B has occurred is 0.43, and the probability of B given A has occurred
Fofino [41]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Expon
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A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms. This can be obtained by understanding what like radicals are.

<h3>Which sets of the radical expressions listed could be considered like terms as written?</h3>
  • Radical expression: Radical expression is an equation that has a variable in a radicand (expression under the root) or has a variable with a rational exponent.

For example, √128, √16

  • Like radicals: Radicals that have the same root number and radicand (expression under the root)

For example, 2√x and 5√x are like terms.

Here in the question radical expressions are given,

  • 5∛2x
  • -4x∛2
  • 5√2x
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  • 5x√2x

By definition of like radicals we get that 5∛2x and -3∛2x are like terms since root number and radicand are same, that is, root number is 3 and radicand is 2x.

Hence A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms.

Learn more about radicals here:

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3 0
2 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
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