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3 years ago

Please help with 14 and 15

Mathematics

1 answer:

o-na [289]3 years ago

4 0

Answer: 14. The three consecutive numbers are 12, 14 and 16.

15. An example of equation whose solution is 5 is given below

2X — 20 = X — 15

Step-by-step explanation: please see attachment for explanation.

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3 years ago

Answer my math question I asked so many times I lost most of points help by

alexandr1967 [171]

y-intercept: (0, 1)

Line of symmetry calculation: x = -b/2a = -(-2)/2(2) = 0.5

Line of symmetry: x = 0.5

Open UP or DOWN: Opens UP

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3 years ago

What is the simplified form of the following expression? 2√27+√12-3√3-2√12

LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$

but

$2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}$

$\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}$

Since √12=2√3,this implies that,

$2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}$

Therefore,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}$

$=(6+2-3-4)\sqrt{3}$

$=\sqrt{3}$

The simplified form of ,

$2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}$ is √3

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3 years ago

Points A, B, and C are collinear. Point B is between A and C, AC=15a-5 , AB=10a+6, and BC=3a+11. Find AB

sdas [7]

Answer:

I bet you're smarter than me so you can figure it out

Step-by-step explanation:

good thing you aint like me

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3 years ago