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2 years ago

Tangle ABC is dilated to create triangle ABC using

Mathematics

1 answer:

solmaris [256]2 years ago

3 0

Answer:

scale factor = 4

Step-by-step explanation:

The scale factor is the ratio of OA' to OA , that is

scale factor = $\frac{OA'}{OA}$ = $\frac{3+9}{3}$ = $\frac{12}{3}$ = 4

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Someone please help me with this one

Anna35 [415]

Answer:

k=-2x+9

Step-by-step explanation:

-4x+6=k*2x-3

+3 +3

-4x+9=k*2x

/2x /2x

-2x+9=k

8 0

3 years ago

Help I need nhelp on this question and no links please

Naddik [55]

Image of answer

I hope that helps

- 4018669

3 0

2 years ago

A restaurant will select 1 card from a bowl to win a free lunch, jimmy puts 10 cards in the bowl. The bowl has a total of 150 ca

Phantasy [73]

The odds of jimmy winning a free lunch is 0.066.

<h3>What is Probability ?</h3>

Probability is the likeliness of an event to happen.

It is given that

A restaurant will select 1 card from a bowl to win a free lunch,

jimmy puts 10 cards in the bowl.

The bowl has a total of 150 cards in it

The odds of jimmy winning a free lunch is given by

= No. of chances / Total Outcomes

= 10/150

= 1/15

= 0.066

Therefore the odds of jimmy winning a free lunch is 0.066.

To know more about Probability

brainly.com/question/11234923

#SPJ1

3 0

2 years ago

The difference of the square of a number and 4 is equal to 3 times that number. Find the positive solution.

liberstina [14]

Let the number be 'a':

The difference of the square of a number and 4

a^2 -4

is equal to 3 times that number.

= 3*a

a^2 -4 =3a

a^2 -3a -4=0

(a-4) (a+1)=0

solutions are: 4 and -1

8 0

2 years ago

Read 2 more answers

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago