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3 years ago

Would you rather...... justify your answer.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

5 0

This question is supposed to be answered by you, not us. Please choose any kind of answer you would like to choose!

(In my opinion, I would choose 4/5)

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Find the slope of the line going through the points (-4, 3) and (-1,-6)

Fed [463]

Answer:

-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=-6-3/-1-(-4)

m=-9/3

m=-3

8 0

3 years ago

Read 2 more answers

brainliest for correct answer A triangle has interior angle measures 28 and 32, please find the 3rd interior angle and two exter

brilliants [131]

Answer:

120

Step-by-step explanation:

All the angles should add up to equal 180 so,

28 + 32 + ? = 180

60 + ? = 180

180 - 60 = 120

7 0

3 years ago

Write the equation of a line that is perpendicular to y = 5 y=5y, equals, 5 and that passes through the point ( − 7 , − 5 ) (−7,

Jlenok [28]

The line of the equation perpendicular to y=5 and cuts through (-5,-7) will be given by
m(x-x1)=y-y1
where m=slope.
from y=0x+5, the slope of the perpendicular line m=0,
thus the equation will be:
0(x--5)=y--7
0=y+7
y=-7
The equation is y=-7

3 0

3 years ago

Read 2 more answers

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

One person can do a certain job in 15 minutes and another person can do the same job in 30 minutes. How many minutes will it tak

Flauer [41]

Hello! Your answer is B, 10 minutes.

Say the x = minutes taken to do the job. You can set up an equation like this to solve this.

$\frac{1}{15} x + \frac{1}{30} x = 1$

This is representative of the situation. The fractions each represent how much each person does in a minute, and when they're multiplied by x, that's how much of the project they get done based off of the minutes they work together on the job. Add the two together, and you get how much of the project is finished in x amount of time. Set it equal to 1, as you are looking for 100% completion.

Once you have this equation, find a common denominator, add, and solve.

$\frac{1}{15} x + \frac{1}{30} x = 1$

$\frac{2}{30} x + \frac{1}{30} x = 1$

$\frac{3}{30}x = 1$

$\frac{1}{10}x = 1$

$x = 10$

Therefore, it will take them 10 minutes to do the job together.

Hope this helps!

8 0

3 years ago