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stepladder [879]
3 years ago
7

Write the equation of the line perpendicular to 2x - 3y = 1 that passes through the point (3,-5) in slope-intercept form and in

standard form.
Mathematics
2 answers:
a_sh-v [17]3 years ago
6 0

Answer:

slope intercept form: 1/2x+3/2yx+16

Step-by-step explanation:

dexar [7]3 years ago
6 0

Answer:

y = -3/2x - 1

Step-by-step explanation:

this line 2x-3y=9 can be rewritten as

y = 2/3x - 3

The slope of this line is 2/3

If two lines are perpendicular, then their slopes satisfy condition

m1 . m2 = -1

Thus, the slope of the needed line is

m = -3/2

The equation of the line passing through the point (2,-4) and perpendicular to the line 2x-3y=9 is

y + 4 = 3/2 (x - 2)

y = -3/2 x - 1

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Help me. Show work. Show equation
xxMikexx [17]
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3 0
3 years ago
Logb(x-1) + logb(x+2) = logb(8-2x)
Aleksandr [31]

Answer:

x=2

Step-by-step explanation:

log_x(y)+log_x(z)=log_x(yz), so logb(x-1) + logb(x+2)=logb((x-1)(x+2)). next subtract logb(8-2x) from both sides to get logb((x-1)(x+2))-logb(8-2x)=0. log_x(y) - log_x(z) = log_x(y/z). so now we have logb((x-1)(x+2)/(8-2x)). now you can put it into exponential form: (x-1)(x+2)/(8-2x)=b^0=1 now just solve for x:

(x-1)(x+2)= 8-2x, x^2 + x -2 = 8-2x, x^2 + 3x -10 = 0, (x+5)(x-2)=0 x=-5, x=2. plug both into the original equation to check which one is correct, since log_x(y) can't have a negative y, x=-5 doesnt work

7 0
2 years ago
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BARSIC [14]
12x = 12; x = 1

That simple
6 0
3 years ago
Identify the segment bisector of QR. Then find QR. *
Fittoniya [83]

Answer:

Ok so QR=10 because x=5 and the bisector I believe is LM :)

Step-by-step explanation:

5 0
3 years ago
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