C. Vertex (x,y). The vertex is right in the middle of the quadratic graph.
It is the area of two triangle and one rectangle
area of a triangle is 1/*b*h
A=1/2*1.9*2.8=2.66 ft^2 multiply it by 2 as we have 2 triangle= 5.32 ft^2
Area of a rectangle=w*l=3.2*2.8 =8.96 ft^2
Add them =8.96+5.32=14.28ft^2
Answer:
The equation is ( x² / 9 ) - ( y² / 7 ) = 1
Step-by-step explanation:
Given the data in question;
hyperbola is centered at the origin, this means h and k are all equals to 0.
Vertices: (-3,0) and (3,0)
Since y-coordinates are constant, this implies it is a hyperbola with horizontal transverse axis.
h - a = -3
0 - a = -3
a = 3
Foci: (-4,0) and (4,0)
h - c = -4
0 - c = -4
c = 4
we know that, for a hyperbola
c² = a² + b²
so
⇒ ( 4 )² = ( 3 )² + b²
16 = 9 + b²
b² = 16 - 9
b² = 7
So the equation for the hyperbola will be;
⇒ ( (x-h)² / a² ) - ( (y-k)² / b² ) = 1
so we substitute
⇒ ( (x-0)² / 3² ) - ( (y-0)² / 7 ) = 1
⇒ ( x² / 3² ) - ( y² / 7 ) = 1
⇒ ( x² / 9 ) - ( y² / 7 ) = 1
Therefore, The equation is ( x² / 9 ) - ( y² / 7 ) = 1
Answer:
a) log 2 (48 ×3 ×9 )
log 2 1296
10.3
b) log 4 24 - log 4 3/4 log 4 2
log 4 36
2.58
Answer:
6509.84 ft to the nearest hundredth.
Step-by-step explanation:
We have a right triangle in which the opposite side is 1479 ft and we need to find the adjacent side:
Tan 12.8 = opposite / adjacent side
tan 12.8 = 1479/ x
x = 1479/tan 12.8
= 6509.84 ft.
