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2 years ago

How to i expand this ? x3 (3x - 5)

Mathematics

1 answer:

Nikitich [7]2 years ago

5 0

Use the distributive formula

a(b - c) = ab - ac

$x^3(3x - 5) = \boxed{\bf{3x^4 - 5x^3}}$

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How do you solve this?

BARSIC [14]

7x+2=5(x-2)
7x+2=5x-10
7x-5x=-10-2
2x=-12
x=-6

Regards M.Y.

6 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

2 years ago

find the slope and y-intercept of the line that is perpendicular to y= -2/3x+5 and passes through the line -6,4

nexus9112 [7]

$y = mx+b\\\\[m is the slope, b is the y-intercept]\\\\y=\frac{2}{3}x+5\\$

That means 2/3 is the slope and 5 is the y-intercept.

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

6 0

2 years ago

The function f(x)=2^x and g(x)=f(x+k). If k=-5,what can be concluded about the graph of g(x)?

melamori03 [73]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}\\
~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}$

$\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind

$\bf f(x)=2^x\qquad 
\begin{cases}
g(x)=f(x+k)&k=5\\
\qquad\quad f(x+5)\\
\qquad \quad 2^{x+5}
\end{cases}$

notice, in g(x)

B = 1, no change from parent

C= +2

8 0

2 years ago

Read 2 more answers

Evaluate 4x exponent 2+ 2x-1 for x=9

olasank [31]

The value of given expression is 341

Solution:

Given that we have to find the value of given expression

Given expression is:

$4x^2 + 2x - 1$

Given value is x = 9

Substitute x = 9 in given expression

$\rightarrow 4(9)^2+2(9) - 1$

Solve the above expression

$\rightarrow 4 \times (9 \times 9) + 18 -1\\\\\rightarrow 4 \times 81 + 17\\\\\text{Multiply the terms 4 and 81 }\\\\\rightarrow 324 + 17\\\\\text{Add the numbers }\\\\\rightarrow 341$

Thus the value of given expression is 341

8 0

2 years ago