Answer:
Step-by-step explanation:
The common difference (d) can be found using the first and 4th terms:
a1 = 3
a4 = a1 +d(4 -1)
-9 = 3 +3d . . . . . simplify
-3 = 1 + d . . . . . . divide by 3
-4 = d . . . . . . . . . subtract 1
Then ...
x = a1 + d = 3 -4 = -1
y = x + d = -1 -4 = -5
The values of x and y are -1 and -5, respectively.
In this sequence, we're given the first term, which is 45.
The difference between each term is -3, which means 3 will be subtracted in each term.
We're asked to find the value of the tenth term, and we can do so by using this formula:
a(n) = a(1) + d(n - 1)
Replace values.
a(10) = 45 + -3(9)
a(10) = 18
<h3>The value of the tenth term is 18.</h3>
so since only 3 out of 11 went to visit then it is simple
since just 3 went and there were 11
3/11 of the students went
Answer: Option B.
Step-by-step explanation:
In the graph we can see the graph of a quadratic equation (from this we could conclude that the graph will not change the current direction for the arms, so the arms will keep going down), and we also can see that as x increases in absolute value, the value of y decreases.
Then we could conclude that as IxI is really big, we will have that f(x) goes to minus infinity
x -->∞, f(x) --> -∞
x--> -∞, f(x) --> -∞
Then the correct option is B
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player 
.
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
