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antiseptic1488 [7]
3 years ago
11

Please help me out! as soon as possible!!! I will give you brainiest!

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

give me brainlyest

Step-by-step explanation:

0 x i took the quiz

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Hey guys ( or gals ) I have no idea what to do please help me.
shepuryov [24]

Answer:

Irrational numbers cannot be written as a fraction, or the ratio of two whole numbers.

You would have to find a GCF (greatest common factor) and multiply it out of the radical.

ex.

\sqrt{6} = 2 x 2 x 2

when you have to multiplier numbers then you can combine two of them to take outside the radical, meaning 2x2x2

2\sqrt{2\\}

so \sqrt{6} would be closest to the positive 2 on the number line and 2 notches.

\sqrt{11}

is an irrational number, so it might fall into 3.3 if turned into a decimal.

Step-by-step explanation:

8 0
2 years ago
Ben got a part-time job.his mom said he must save at least two-thirds of his weekly paycheck,and can spend the rest. if he wishe
Viefleur [7K]
So 2/3 of 120 is 80
120-80=40 So it's
120
6 0
3 years ago
Someone start a convo in the comments or try and message me idk how
ivanzaharov [21]

Answer:

Brainly is a platform that is used to help students in need. There are many social networks that offer socializing with many people from every country in the world.

I suggest you install any of those apps, and try find someone to talk to.

On this platform, we offer knowledge and help when it comes to important tests, quizzes and other knowledge-related topics.

Hope I helped.

6 0
3 years ago
Assume that 33.4% of people have sleepwalked. Assume that in a random sample of 1459 ​adults, 526 have sleepwalked.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given that  33.4% of people have sleepwalked.

Sample size n =1459

Sample favourable persons = 526

Sample proportion p = \frac{526}{1459} \\=0.361

Sample proportion p is normal for large samples with mean = 0.334 and

std error = \sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.334(1-0.334)}{1459} } \\=0.0123

a) P(526 or more of the 1459 adults have sleepwalked.)

=P(p\geq 0.361)\\=P(Z\geq \frac{0.361-0.334}{0.0123} \\=P(Z\geq 2.20)\\=0.5-0.4861\\=0.0139

b) Yes, because hardly 1.4% is the probability

c) 33.4 is very less compared to the average.  Either sample should be improved representing the population or population mean should be increased accordingly.

7 0
3 years ago
Aye yall can ya help me pls ill give u brainlest as well but pls dont report or answer ignorant
arlik [135]

Answer:

6-A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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