Answer:
b
Step-by-step explanation:
B. Y= (x - 10) ^ 4 - 81 OR y = x^4 - 20x +91
We have to solve two inequations:
Equation 1:
30(x-1)≥0
(x-1)≥0/30
(x-1)≥0
x≥1 (solution 1)
Equation 2:
5x²≥0
x≥0
The solution is: solution1 <span>∩ solution2
Teherefore; x≥1</span>
Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
Answer:
51.2
Step-by-step explanation:
Answer:
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